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Tasya [4]
3 years ago
7

What is the name for the lowest layer of the atmosphere, which is most influenced by human activities?

Chemistry
2 answers:
bagirrra123 [75]3 years ago
7 0
The Answer Is B Because You Have To Divide The 9
Liula [17]3 years ago
3 0

The name for the lowest layer of the atmosphere, which is most influenced by human activities is the troposphere. The correct answer is D.

The troposphere refers to the lowest layer of the atmosphere. Almost all the weather conditions take place in the troposphere; it is made up of 75 percent of the entire atmosphere mass.

Further Explanation

The Troposphere also contains 99 percent of the entire mass of water vapor and its height differs in trophic, middle latitudes and within the polar region in winter.

The height of the troposphere in the polar region in winter is 6km, which is 20,000 ft., the height of the troposphere in the middle latitudes is 17km, which is 56 000 ft., and its height in the tropics is 18km, which is 59,000 ft. Also, the entire height of the troposphere is 13km.

Within the troposphere, the area where friction with the Earth’s surface impacts airflow is known as the planetary boundary layer.

The deepness of the planetary boundary layer is usually 2 km. The tropopause can be found above the troposphere and it is the boundary between the stratosphere and the troposphere.

Therefore, the name for the lowest layer of the atmosphere, which is most influenced by human activities is the troposphere.

LEARN MORE:

  • What is the name for the lowest layer of the atmosphere, which is most influenced by human activities?  brainly.com/question/2167800
  • What is the name for the lowest layer of the atmosphere, which is most influenced by human activities?  brainly.com/question/3390601

KEYWORDS:

  • troposphere
  • earth's surface
  • human activities
  • atmosphere
  • lowest layer
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Natali [406]

The individual mass of C, H and O in given sample are 0.5196 g, 0.0374 g and 0.1979 g respectively.

Moles of CO2 formed can be calculated as

= Mass of CO2 / Molar mass of CO2

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<h3>Calculation of no. of moles of carbon</h3>

Now, moles of C which is present in one mole of CO2 = 1 mole

Moles of C in 0.0433 moles of CO2 = 0.0433 moles

As we know that, molar mass of C = 12 g / mol

Mass of C in 0.7549 g of given sample can be calculated as

= 0.0433 × 12 =0.5196 g

Mass of H2O formed = 0.3370 g

Similarly, Molar Mass of H2O = 18 g / mol

Moles of H2O = 0.3370 / 18 = 0.0187 moles

Moles of H present in 1 mole of H2O = 2 moles

Moles of H present in 0.0187 mole of H2O = 2 × 0.0187 = 0.0374 moles

Molar mass of H = 1 g / mol

Mass of H contained in 0.7549 g of sample = 1 × 0.0374= 0.0374 g

Mass of O in 0.7549 g sample can be calculated as

= 0.7549 – [(Mass of C ) + (Mass of H) ]

= 0.7549 – [ (0.5196) + (0.0374) ]

= 0.1979 g

Thus, we calculated that the individual mass of C, H and O in given sample are 0.5196 g, 0.0374 g and 0.1979 g respectively.

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DISCLAIMER: THE above question is incomplete. Complete question is given below:

A 0.7549g sample of the compound burns in o2(g) to produce 1.9061g of co2(g) and 0.3370g of h2o(g). Calculate the individual mass of C, H and O in the given sample.

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1 year ago
A + B = AB
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The greatest amount of AB would be produced if the equilibrium constant of the reaction is equal to 1.0 \;X \;10^5. Hence, option D is correct.

<h3>What is an equilibrium constant?</h3>

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The equilibrium constant expression is a mathematical relationship that shows how the concentrations of the products vary with the concentration of the reactants.

If the value of K is greater than 1, the products in the reaction are favoured. If the value of K is less than 1, the reactants in the reaction are favoured.

Hence, option D is correct.

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