All categories

3 years ago

How does the speed of an object influence its momentum

Physics

1 answer:

Akimi4 [234]3 years ago

3 0

momentum = mass* velocity(speed)

due to that, the greater the speed the greater is its momentum

You might be interested in

How can you use litmus paper to distinguish an acid from a base?

11Alexandr11 [23.1K]

Hello! When litmus paper is placed in an acid, it usually turns red. When it is placed in a base, it turns dark-purple. Hope this helps! :)

7 0

3 years ago

Object A weighs 750 N on earth. Object B weighs 750 N on Jupiter.

Katarina [22]

The object A has the greater mass compared to object B.

<u>Explanation: </u>

The weight of any object on any planet is the measurement of gravity’s influence acting on the mass of the object. So for Earth, the acceleration will be acting on the object A’s mass (m) in Earth leading to the weight of the object A as 750 N.

While the acceleration of Jupiter will be acting on the object B’s mass kept in Jupiter to attain the weight of 750 N. So, the mass of both the objects at their respective planet will vary depending on the acceleration of each planet. We can check this as below:

$\text { object A's weight }=\text { m of object A } \times \text { Acceleration of Earth}$

So,

$750 \mathrm{N}=\text { m of object } A \times 9.8 \mathrm{m} / \mathrm{s}^{2}$

Thus,

$\text { m of object } A=\frac{750}{9.8}=76.5 \mathrm{kg}$

Similarly for object B,

$\text { Weight of object } B=m \text { of object } B \times \text { Acceleration due to gravity of Jupiter }$

$750 = m \text { of object } B \times 24.79 \mathrm{m} / \mathrm{s}^{2}$

Thus,

$\text { m of the object } B=\frac{750}{24.79}=30.25 \mathrm{kg}$

Thus, the mass of object A is greater than the mass of object B.

5 0

3 years ago

Which of the following is the water cycle process where the extra water that plants release is evaporated from their leaves?

ddd [48]

B evaporation since the water is going up

6 0

3 years ago

A 420-turn circular coil with an area of 0.0650 m2 is mounted on a rotating frame, which turns at a rate of 22.3 rad/s in the pr

Ivenika [448]

Answer:

33.48 V

Explanation:

Parameters given:

Number of turns, N = 420

Magnetic field strength, B = 0.055 T

Area, A = 0.065 m²

Angular velocity, ω = 22.3 rad/s

EMF induced in a coil is given as:

EMF = -dΦ/dt

where Φ = magnetic flux

Magnetic flux, Φ, is given as:

Φ = B * N * A * cosωt

EMF = -d( B * N * A * cosωt) / dt

EMF = B * N * A * ω * sinωt

where ωt = 90°

Therefore:

EMF = 0.055 * 420 * 0.065 * 22.3 * sin90°

EMF = 33.48 V

7 0

3 years ago

Two particles are traveling through space. At time t the first particle is at the point (−1 + t, 4 − t, −1 + 2t) and the second

Pie

Answer:

Yes, the paths of the two particles cross.

Location of path intersection = ( 1 , 2 , 3)

Explanation:

In order to find the point of intersection, we need to set both locations equal to one another. It should be noted however, that the time for each particle can vary as we are finding the point where the <u>paths</u> meet, not the point where the particles meet themselves.

So, we can name the time of the first particle $T_F$ , and the time of the second particle $T_S$ .

Setting the locations equal, we get the following equations to solve for $T_F$ and $T_S$ :

$(-1 + T_F) = (-7 + 2T_S)$ Equation 1

$(4 - T_F) = (-6 + 2T_S)$ Equation 2

$(-1 + 2T_F) = (-1 + T_S)$ Equation 3

Solving these three equations simultaneously we get:

$T_F =$ 2 seconds

$T_S =$ 4 seconds

Since, we have an answer for when the trajectories cross, we know for a fact that they indeed do cross.

The point of crossing can be found by using the value of $T_F$ or $T_S$ in the location matrices. Doing this for the first particle we get:

Location of path intersection = ( -1 + 2 , 4 - 2 , -1 + 2(2) )

Location of path intersection = ( 1 , 2 , 3)

5 0

3 years ago