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insens350 [35]
3 years ago
13

A science class puts a balloon containing 1.25 l of air at 101 kpa into a bell jar. using an air pump, the class removes some of

the air in the jar, causing the balloon to expand to a volume of 2.25 l. assuming a constant temperature, what is the new pressure inside the jar?
Physics
1 answer:
storchak [24]3 years ago
8 0
The first thing you should know in this case is the following definition:
 PV = nRT
 Then, as the temperature is constant, then:
 PV = k
 Then, we have two states:
 P1V1 = k
 P2V2 = k
 We can then equalize both equations:
 P1V1 = P2V2
 Substituting the values:
 (1.25) * (101) = (2.25) * (P2)
 Clearing P2:
 P2 = ((1.25) * (101)) /(2.25)=56.11Kpa
 answer:
 the new pressure inside the jar is 56.11Kpa
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A 2.3 m long wire weighing 0.075 N/m is suspended directly above an infinitely straight wire. The top wire carries a current of
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Answer:

Explanation:

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B =  10⁻⁷ x \frac{2\times49}{r}

force on second wire per unit length

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=  10⁻⁷ x \frac{2\times49}{r} x 33 x 1

= 3234 x \frac{10^{-7}}{r}

This should balance weight of second wire per unit length

3234 x \frac{10^{-7}}{r} = .075

r = \frac{3234}{.075} x 10⁻⁷

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3 years ago
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Answer:

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Explanation:

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2 years ago
If a point has 40 J of energy and the electric potential is 8 V, what must be the charge?
Alekssandra [29.7K]

If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C

<u>Given the following the details;</u>

  • Energy = 40 Joules
  • Electric potential = 8 Volts

To find the quantity of charge;

Mathematically, the quantity of charge with respect to electric potential is given by the formula;

Quantity \; of \; charge = \frac{Energy}{Electric \; potential}

Substituting the values into the formula, we have;

Quantity \; of \; charge = \frac{40}{8}

<em>Quantity of charge = 5 Coulombs</em>

Therefore, the quantity of charge must be <em>5 Coulombs.</em>

Find more information: brainly.com/question/21808222

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3 years ago
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a driver travels 135 km, east in 1.5 h, stops for 45 minutes for lunch, and then resumes driving for the next 2.0 h through a di
daser333 [38]

Answer:

v = 98.75 km/h

Explanation:

Given,

The distance driver travels towards the east, d₁ = 135 km

The time period of the travel, t₁ = 1.5 h

The halting time, tₓ = 46 minutes

The distance driver travels towards the east, d₂ = 215 km

The time period of the travel, t₁ = 2 h

The average speed of the vehicle before stopping

                                    v₁ = d₁/t₁

                                        = 135/1.5

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The average speed of vehicle after stopping

                                    v₂ = d₂/t₂

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The total average velocity of the driver

                                      v = (v₁ +v₂) /2

                                         = (90 + 107.5)/2

                                         = 98.75 km/h

Hence, the average velocity of the driver, v = 98.75 km/h

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3 years ago
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