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Vika [28.1K]
3 years ago
8

Planets move around the sun in elliptical orbits. True. False

Physics
2 answers:
aleksley [76]3 years ago
8 0

TRUE TRUE TRUE TRUE TRUE TRUE

astra-53 [7]3 years ago
5 0

this answer is true.

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If a polar is swimming with an average of 2.6 m/s how far will it traveled after 120 seconds ?
iragen [17]

Distance= speed x time

distance = 2.6 m/s x 120s

distance= 312 meters

6 0
3 years ago
You are pushing a heavy box across a rough floor. when you are initially pushing the box and it is accelerating, (a) you exert a
kodGreya [7K]

The answer is C. If the box is accelerating, that means that the amount of force you are exerting is greater than the force of the box.

3 0
3 years ago
Read 2 more answers
A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 6 ft from the path and is kept fo
BARSIC [14]

We are given that,

\frac{dx}{dt} = 4ft/s

We need to find \frac{d\theta}{dt} when x=8ft

The equation that relates x and \theta can be written as,

\frac{x}{6} tan\theta

x = 6tan\theta

Differentiating each side with respect to t, we get,

\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}

\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}

\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}

Replacing the value of the velocity

\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2

\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta

The value of cos \theta could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to

cos\theta = \frac{6}{10}

\frac{d\theta}{dt} = \frac{8}{3} (\frac{6}{10})^2

\frac{d\theta}{dt} = \frac{24}{25}

Search light is rotating at a rate of 0.96rad/s

4 0
3 years ago
A student observes that it is hard to hear music underwater in a pool. They state that the sound is always muffled. They
s344n2d4d5 [400]

Answer:

FALSE      

Explanation:

The answer is false.

The speed of the sound in water is  faster when compared to the speed of sound in air. This is because, the particles in air is loosely packed and are far from each other as compared to water or liquid.

The water particles are close to each other than air particles, so water particles are able to transmit the vibrations of the sound faster than the air particles.

Therefore sound waves travels faster in water than in air.

5 0
3 years ago
A closed system:
adoni [48]
The answer is b i just did the test
3 0
2 years ago
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