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maxonik [38]
3 years ago
15

I need help with science plz and ty( plz dont give me helpless answer)

Physics
2 answers:
muminat3 years ago
8 0
1. D
2. A
I’m not sure on 3
Ierofanga [76]3 years ago
6 0
1.) D
2.) A
3.) C
i hope this helps!
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An object on the surface of the earth weighs 90 lb. At two earth radii above the surface, It will welgh:
vredina [299]
I have no explanation, but saw this pop up on a test paper and the answe was 10lb
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How many steps are there in the formation of a solar system?
FromTheMoon [43]
There are six steps on the formation of a solar system. 1) solar nebula
2) planetesimals form. 3) planetesimals accrete into protoplanest 4) terrestrial planets form 5) gas giants form 6) formation or organization of smaller objects (moon, asteroids, comets)
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A force of 100 newtons Is applled to a box at an angle of 36° with the horizontal. If the mass of the box Is 25 kilograms, what
faust18 [17]
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5 0
3 years ago
How many lines per mm are there in the diffraction grating if the second order principal maximum for a light of wavelength 536 n
grandymaker [24]

To solve this problem it is necessary to apply the concepts related to the principle of superposition and the equations of destructive and constructive interference.

Constructive interference can be defined as

dSin\theta = m\lambda

Where

m= Any integer which represent the number of repetition of spectrum

\lambda= Wavelength

d = Distance between the slits.

\theta= Angle between the difraccion paterns and the source of light

Re-arrange to find the distance between the slits we have,

d = \frac{m\lambda}{sin\theta }

d = \frac{2*536*10^{-9}}{sin(24)}

d = 2.63*10^{-6}m

Therefore the number of lines per millimeter would be given as

\frac{1}{d} = \frac{1}{2.63*10^{-6} }

\frac{1}{d} = 379418.5\frac{lines}{m}(\frac{10^{-3}m}{1 mm})

\frac{1}{d} = 379.4 lines/mm

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6 0
3 years ago
What is the kinetic energy of a an 80kg football player running at 8 m/s?
Ugo [173]
In the question it is already given that the football player is 80 kg.
Then the mass of the football player = 80 kg
Velocity at which the football player is running = 8 m/s
<span>Kinetic Energy = 0.5 • mass • square of velocity
Now we have to put the known data in this equation to find the actual velocity of the footballer.
</span> <span></span>So
Kinetic Energy of the footballer = 0.5 * 80 * (8 * 8)
                                                 = 0.5 * 80 * 64
                                                 = 2560
So the Kinetic energy of the footballer is 2560 joules


4 0
3 years ago
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