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Kisachek [45]
3 years ago
5

What is the 6th term in the sequence below? 4,-8, 16, -32,

Mathematics
2 answers:
AURORKA [14]3 years ago
4 0

Answer:

−128

Step-by-step explanation:

BartSMP [9]3 years ago
4 0

<em>Assuming the pattern continues...</em>

Answer:

128

Step-by-step explanation:

We see that this is a geometric series with common ratio -2.

So, the 6th term is the 4th term times (-2)^2=2^2=4.

So, the answer is 4(-32)=\boxed{128} and we're done!

Note:

The closed form for this geometric series is 4*(-2)^{n-1}, which means the nth term is always 4*(-2)^{n-1}.

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choli [55]

Answer:

Sin(F)  = 12/13

Cos(F)  = 5/13

Tan(F) = 12/5

Step-by-step explanation:

Sin = Opp./Hypo, Cos = Adj./Hypo. and Tan = Opp./Adj.

So

Sin(F) = Opp./Hypo = 12/13

Cos(F) = Adj./Hypo = 5/13

Tan(F) = Opp./Adj. = 12/5

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E = 7
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First find a number that multiplies by 4 to make a number ending in 2. The options are either 3 or 8.
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