Question

What is the 6th term in the sequence below? 4,-8, 16, -32,

Answer 1

Answer:

−128

Step-by-step explanation:

Answer 2

Assuming the pattern continues...

Answer:

$128$

Step-by-step explanation:

We see that this is a geometric series with common ratio $-2$.

So, the 6th term is the 4th term times $(-2)^2=2^2=4$.

So, the answer is $4(-32)=\boxed{128}$ and we're done!

Note:

The closed form for this geometric series is $4*(-2)^{n-1}$, which means the nth term is always $4*(-2)^{n-1}$.