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IrinaVladis [17]
2 years ago
11

What is the answer too: Mrs Jones decides to buy Christmas presents for her nieces and nephews in the museum. She buys:

Mathematics
1 answer:
Anna35 [415]2 years ago
6 0

Answer:

7k + 5s = y

v = k + s

Step-by-step explanation:

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Which matrix is equal to
just olya [345]

Answer:

L

O

+

65.91828182

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
At first it decreased by 60 percent and it increased by 80 percent
storchak [24]

The quantity reported an <em>equivalent net</em> percentage change of 28 percent.

<h3>How to calculate the net change of a quantity in percentages</h3>

In this problem we must determine the <em>simple</em> percentage change equivalent to two <em>consecutive</em> percentual changes. The formula that describes the situation is:

1 + r/100 = (1 - 60/100) · (1 + 80/100)

1 + r/100 = 72/100

r/100 = - 28/100

r = - 28

The quantity reported an <em>equivalent net</em> percentage change of 28 percent.

<h3>Remark</h3>

The statement is incomplete. Complete form is presented below:

A quantity is changing. At first it descreased by 60 percent and it increased by 80 percent. What is net change of the quantity in percentage?

To learn more on percentages: brainly.com/question/13450942

#SPJ1

5 0
1 year ago
I have $3,800 in two accounts for one year. The first account earns a yearly interest of 3.5%. The second account earns a yearly
loris [4]

Answer:

-$1000

Step-by-step explanation:

(3800 - x)*3.5/100 = (3800 + x)*6/100

(3800 - x)7/200 = 3/50(3800 + x)

3800 - x = 12/7(3800 + x)

3800 - x = 45600/7 + 12x/7

(19x + 19000)/7 = 0

19x = -19000

x = -$1000.

The minus implies that the investment must occur in the first account, not the second. It wouldn't make sense to add more money into the second account, because the second account already exceeds the $188 interest with the amount it has in there. Therefore $1000 must be added from the second account and invested into the first.

3 0
3 years ago
4. A statistician working for the National Basketball Association supplies the television announcers with interesting statistics
Sonbull [250]

Answer: 0.038

Step-by-step explanation:

Given: Total games : n= 375

Number of games won by  the team that was winning the game at the end of the third quarter. = 300

The proportion (p) of the team that was winning the game at the end of the third quarter: p=\dfrac{300}{375}=0.8

Critical z-value for 90% confidence: z* = 1.645

Margin of error =z^*\sqrt{\dfrac{(1-p)p}{n}}

The margin of error in a 90% confidence interval estimate of p =1.645\sqrt{\dfrac{0.2\times0.8}{300}}\\= 1.645\times\sqrt{0.00053333}\\\\=1.645\times0.0231\\\\=0.0379995\approx$$0.038

Hence, the required margin of error = 0.038

7 0
3 years ago
Please help me with both! would really appreciate it
Tamiku [17]
Jus look and the answer above
7 0
3 years ago
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