All categories

3 years ago

EMERGENCY PLEASE HELP!!!! I NEED ONE OF MY MATH QUESTIONS ANSWERED

Mathematics

2 answers:

dmitriy555 [2]3 years ago

6 0

Answer:

whats the question

Step-by-step explanation:

-BARSIC- [3]3 years ago

4 0

Answer:

Hi!

What is the math question?

-Mikayla

You might be interested in

Which graph represents the solution set of the inequality x+2>6

Andreyy89

Answer:

x + 2 < 6

x < 4

d represents the inequality

3 0

3 years ago

Read 2 more answers

Daniel baked 59 cinnamon rolls. He sold 30 to one customer and 2 packages of 6 to another. He gave away to friends. How many wer

Marianna [84]

The answer would be 17 because 59 - 30 = 29 and 29 - 12 =17

6 0

3 years ago

Strain-displacement relationship) Consider a unit cube of a solid occupying the region 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, 0 ≤ z ≤ 1 After loa

Anastasy [175]

Answer:

please see answers are as in the explanation.

Step-by-step explanation:

As from the data of complete question,

$0\leq x\leq 1\\0\leq y\leq 1\\0\leq z\leq 1\\u= \alpha x\\v=\beta y\\w=0$

The question also has 3 parts given as

Part a: Sketch the deformed shape for α=0.03, β=-0.01 .

Solution

As w is 0 so the deflection is only in the x and y plane and thus can be sketched in xy plane.

the new points are calculated as follows

Point A(x=0,y=0)

Point A'(x+αx,y+βy)

Point A'(0+(0.03)(0),0+(-0.01)(0))

Point A'(0,0)

Point B(x=1,y=0)

Point B'(x+αx,y+βy)

Point B'(1+(0.03)(1),0+(-0.01)(0))

Point B'(1.03,0)

Point C(x=1,y=1)

Point C'(x+αx,y+βy)

Point C'(1+(0.03)(1),1+(-0.01)(1))

Point C'(1.03,0.99)

Point D(x=0,y=1)

Point D'(x+αx,y+βy)

Point D'(0+(0.03)(0),1+(-0.01)(1))

Point D'(0,0.99)

So the new points are A'(0,0), B'(1.03,0), C'(1.03,0.99) and D'(0,0.99)

The plot is attached with the solution.

Part b: Calculate the six strain components.

Solution

Normal Strain Components

$\epsilon_{xx}=\frac{\partial u}{\partial x}=\frac{\partial (\alpha x)}{\partial x}=\alpha =0.03\\\epsilon_{yy}=\frac{\partial v}{\partial y}=\frac{\partial ( \beta y)}{\partial y}=\beta =-0.01\\\epsilon_{zz}=\frac{\partial w}{\partial z}=\frac{\partial (0)}{\partial z}=0\\$

Shear Strain Components

$\gamma_{xy}=\gamma_{yx}=\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x}=0\\\gamma_{xz}=\gamma_{zx}=\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x}=0\\\gamma_{yz}=\gamma_{zy}=\frac{\partial w}{\partial y}+\frac{\partial v}{\partial z}=0$

Part c: Find the volume change

$\Delta V=(1.03 \times 0.99 \times 1)-(1 \times 1 \times 1)\\\Delta V=(1.0197)-(1)\\\Delta V=0.0197\\$

Also the change in volume is 0.0197

For the unit cube, the change in terms of strains is given as

$\Delta V={V_0}[(1+\epsilon_{xx})]\times[(1+\epsilon_{yy})]\times [(1+\epsilon_{zz})]-[1 \times 1 \times 1]\\\Delta V={V_0}[1+\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}+\epsilon_{xx}\epsilon_{yy}+\epsilon_{xx}\epsilon_{zz}+\epsilon_{yy}\epsilon_{zz}+\epsilon_{xx}\epsilon_{yy}\epsilon_{zz}-1]\\\Delta V={V_0}[\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\$

As the strain values are small second and higher order values are ignored so

$\Delta V\approx {V_0}[\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\ \Delta V\approx [\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\$

As the initial volume of cube is unitary so this result can be proved.

5 0

3 years ago

In the United States, there are 59 different species of mammals that are endangered,

jolli1 [7]

Given Information:

Number of endangered mammal species = 59

Number of endangered bird species = 75

Number of endangered fish species = 68

Required Information:

Probability of either a mammal or a fish = ?

Answer:

P(mammal or fish) = 127/202 = 0.6287 = 62.87%

Step-by-step explanation:

We want to randomly select one animal and find out the probability of either a mammal or a fish.

The total number of endangered species of animals is given by

Total animals = mammal species + bird species + fish species

Total animals = 59 + 75 + 68 = 202

The probability of selecting a endangered mammal is

P(mammal) = no. of endangered mammal/total no. of endangered animals

P(mammal) = 59/202

The probability of selecting a endangered fish is

P(fish) = no. of endangered fish/total no. of endangered animals

P(fish) = 68/202

Finally, the probability of selecting either a mammal or a fish is

P(mammal or fish) = 59/202 + 68/202

P(mammal or fish) = 127/202

P(mammal or fish) = 0.6287

P(mammal or fish) = 62.87%

8 0

3 years ago

What is the range of this function?

Mariana [72]

Answer:

D. {-8, -5, 3, 7}

Step-by-step explanation:

__________

3 0

3 years ago