A student practicing for a track meet ran 3500 m in 500 s. What was her average speed? a. 4,000 m/s b. 0.14 m/s c. 7 m/s d. 1,75
1 answer:
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Answer:
I = 11.26 mA
Explanation:
given,
V = 0.7 V length = 80 m
diameter = 0.2 mm = 0.02 cm
radius = 0.01 × 10⁻² m
ρ for gold wire = 2.44 × 10⁻⁸ ohm-m at 20 °C
A = cross sectional area = π r² = π (0.01 × 10⁻² )²
= 31.4× 10⁻⁹ m²
R = 62.165 Ω
I = 11.26 mA
Answer:
The tension is 14 N
Explanation:
For this problem we have to use newton's law, so:
The second string is connected to the mass of 8 kg, but the mass of 8 kg is connected to the mass of 20kg, so we can say that the second string is handling the two masses. so: