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4 years ago

How is the control group and experimental group different

1 answer:

4 0

The control group is the independent variable and the experimental group is the dependent due to change during the experiment. The experimental group will usually rely on another variable in the experiment for change.

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The air around a pool and the water in the pool receive equal amounts of energy from the sun. Why does the air experience a grea

labwork [276]

Answer:

Explanation:

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3 years ago

Whats 46/50 as a percent?

Gelneren [198K]

92 percent because you multiply it by 2

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4 years ago

Read 2 more answers

If |v|= 11, |w|= 23, |v-w|= 30, find |v+w|

GenaCL600 [577]

Answer:

$|v+w|=20$

Explanation:

We are given that

|v|=11

|w|=23

|v-w|=30

We have to find the value of |v+w|

|a-b|^2=(a+b)\cdot (a+b)=a^2+b^2-2|a||b|cos\theta

Using the formula

$(30)^2=(11)^2+(23)^2-2(11)(23)cos\theta$

$900=121+529-506cos\theta$

$900-121-529=-506cos\theta$

$250=-506cos\theta$

$cos\theta=-\frac{250}{506}$

$|a+b|^2=|a|^2+|b|^2+2a\cdot bcos\theta$

Using the formula

$|v+w|^2=(11)^2+(23)^2+2(11)(23)\times (-\frac{250}{506})$

$|v+w|^2=400$

$|v+w|^2=(20)^2$

$|v+w|=20$

7 0

3 years ago

In a Rutherford scattering experiment a target nucleus has a diameter of 1.34×10-14 m. The incoming α particle has a mass of 6.6

Rasek [7]

Answer:

E = 2.5 x 10⁻¹⁴ J

Explanation:

given,

diameter = 1.33 x 10⁻¹⁴ m

mass = 6.64 x 10⁻²⁷ kg

wavelength is equal to diameter

de broglie wavelength equal to diameter

$\lambda = \dfrac{h}{mv}$

$1.33 \times 10^{-14}= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times v}$

$v= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times 1.33 \times 10^{-14}}$

v = 7.5 x 10⁶ m/s

Kinetic energy is equal to

$E = \dfrac{1}{2}mv^2$

$E = \dfrac{1}{2}\times 6.64 \times 10^{-27}\times (7.5\times 10^6)^2$

E = 2.5 x 10⁻¹⁴ J

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3 years ago

The antiseptics used for cuts and wounds in human flesh have low surface tension. Why?

lakkis [162]

Because liquids with low surface tension spread easily, and therefore are easier to apply to cuts and wounds.

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3 years ago