2 years ago

How do positive charges in an electric field move?

Physics

1 answer:

astraxan [27]2 years ago

7 0

Answer:

DOG

Explanation:

jk jk left to right

You might be interested in

The total resistance of a 15-ohm, an 65-ohm and a 35-ohm resistor connected in parallel

yanalaym [24]

Answer:

I think its 9.0397 Ohms

Explanation:

take the reciprocal of all the resistances: 1/15, 1/65, 1/35

then add them: = 151/1365

then reciprocal the answer: =1365/151

And chuck it on a calculator: =9.04 Ohms

I think this is right but I'm not entirely sure. Tell me if I'm right by the way!

3 0

2 years ago

A spherical hot air balloon of diameter 30.0 meters just floats (hovers) when the hot air inside has been heated to a density of

Rom4ik [11]

Answer:

W = 166422.729 N

Explanation:

given,

diameter of the balloon = 30 m

density of the air = 1.10 Kg/m³

weight of the balloon and cargo = ?

density of the surrounding air = 1.20 kg/m³

we know,

Density = mass/volume

m = density x volume

$m = \rho\times \dfrac{4}{3}\pi r^3$

$m =1.20 \times \dfrac{4}{3}\pi\times 15^3$

m = 16964.6 Kg

Weight of the balloon

W = m g

W = 16964.6 x 9.81

W = 166422.729 N

Weight of the balloon and the cargo is equal to W = 166422.729 N

5 0

2 years ago

VARVARA [1.3K]

B. they had different beliefs and backgrounds.

3 0

3 years ago

As computer information technology becomes faster, how does the ability of scientists to collect and organize data change?

Andreas93 [3]

Because computers and technology develop and become faster things are going to become substantially easier.

6 0

2 years ago

Read 2 more answers

Since force is dp/dt, the force due to radiation pressure reflected off of a solar sail can be calculated as 2 times the radiati

QveST [7]

Answer:

8.67×10⁻⁶ N/m²

Explanation:

p = Momentum of a photon

E = Energy of a photon

c = Speed of light

I = Intensity of light

Force = dp/dt

$p=\frac{E}{c}$

$\\\Rightarrow F=\frac{\frac{dE}{dt}}{c}$

As given in question

$F=2\frac{\frac{dE}{dt}}{c}$

Now F/A = Pressure

$P=\frac{2I}{c}\\\Rightarrow P=\frac{2\times 1300}{3\times 10^{8}}\\\Rightarrow P=8.67\times 10^{-6}\ N/m^2$

∴ Magnitude of the pressure on the sail is 8.67×10⁻⁶ N/m²

4 0

3 years ago