Answer:
a) T = (m1cT1 + m2cT2 - m2Lf)/(m1c + m2c)
b) T = 295.37 K
Explanation:
Given;
Initial temperature of tea T1 = 31 C
Initial temperature of ice T2 = 0 C
Mass of tea m1 = 0.89 kg
Mass of ice m2 = 0.075kg
The heat capacity of both water and tea c = 4186 J/(kg⋅K)
the latent heat of fusion for water is Lf = 33.5 × 10^4 J/kg
And T = the final temperature of the mixture
Heat loss by tea = heat gained by ice
m1c∆T1 = m2c∆T2 + m2Lf
m1c(T1-T) = m2c(T-T2) + m2Lf
m1cT1 - m1cT = m2cT - m2cT2 + m2Lf
m1cT + m2cT = m1cT1 + m2cT2 - m2Lf
T(m1c + m2c) = m1cT1 + m2cT2 - m2Lf
T = (m1cT1 + m2cT2 - m2Lf)/(m1c + m2c)
Substituting the values;
T = (m1cT1 + m2cT2 - m2Lf)/(m1c + m2c)
T = (0.89×4186×31 + 0.075×4186×0 - 0.075×33.5 × 10^4)/(0.89×4186 + 0.075×4186)
T = 22.37 °C
T = 273 + 22.37 K
T = 295.37 K
Try this solution (if it is possible, check it in other sources):
1. for m_Tarzan=75kg., initial_height=4m., end_height=0 m. and g=10 N/kg. Energy is:
2. The same value of Energy is applied for m_Tarzan+Jane=75+50=125 kg.:
3. According to the formula of the Speed:
Speed=sqrt(6000/125)=sqrt(48)=4sqrt(3)≈4*1.71=6.84 (m/s)
Answer: 6.84 (m. per sec.)
The cheetah needs 197.8 seconds to complete the 5.50 *100 m distance.
The distance traveled divided by the time taken is the most popular formula for calculating average speed. The average speed is determined by dividing the whole distance by the total time required to complete the distance. The other calculation, provided you have the initial and final speeds, adds them together and divides by 2.20. calculating the time needed for a cheetah to travel 5.50 102 meters.
10 km/h average speed is equal to 10 / 3.6, or 2.78 m/s.
Dist. = 5.50 102
Time =?
average speed = time / distance
time=5.50 x 100/ 2.78
Time = 197.8 s
Therefore, it takes a cheetah 197.8 seconds to travel 5.50 102 meters.
Learn more about average speed here-
brainly.com/question/12322912
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Answer:
S = 26.58 meters
Explanation:
Given the following data;
Initial velocity = 4.66 m/s
Acceleration = 5.66 m/s²
Time = 2.35 seconds
To find the distance travelled by the object, we would use the second equation of motion;
S = ut + ½at²
Where;
S represents the displacement or height measured in meters.
u represents the initial velocity measured in meters per seconds.
t represents the time measured in seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
S = 4.66*2.35 + ½*5.66*2.35²
S = 10.951 + (2.83 * 5.5225)
S = 10.951 + 15.629
S = 26.58 meters
I think so yeah if I’m not right sorry
