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3 years ago

14

The soccer player is running at a speed of 4m/s when he slides on the ground, coming to a stop distance of 2m. What is the accel

eration?

1 answer:

kirill115 [55]3 years ago

4 0

Acceleration=change of velocity
---------------------------
Time

a= v-u
-----
T

a= 2m
------
4m/s
a=8ms-2

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How many visible stars does How many visible stars Taurus “the bull” have

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The Taurus "bull" is home to 500 stars, six of which are visible to the naked eye.

Explanation:

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Air escaping out from an air hose at a gas station always feels cool. Why?

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2 years ago

A long, thin rod parallel to the y-axis is located at x = - 1 cm and carries a uniform positive charge density λ = 1 nC/m . A se

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Answer:

The electric field at origin is 3600 N/C

Solution:

As per the question:

Charge density of rod 1, $\lambda = 1\ nC = 1\times 10^{- 9}\ C$

Charge density of rod 2, $\lambda = - 1\ nC = - 1\times 10^{- 9}\ C$

Now,

To calculate the electric field at origin:

We know that the electric field due to a long rod is given by:

$\vec{E} = \frac{\lambda }{2\pi \epsilon_{o}{R}$

Also,

$\vec{E} = \frac{2K\lambda }{R}$ (1)

where

K = electrostatic constant = $\frac{1}{4\pi \epsilon_{o} R}$

R = Distance

$\lambda$ = linear charge density

Now,

In case, the charge is positive, the electric field is away from the rod and towards it if the charge is negative.

At x = - 1 cm = - 0.01 m:

Using eqn (1):

$\vec{E} = \frac{2\times 9\times 10^{9}\times 1\times 10^{- 9}}{0.01} = 1800\ N/C$

$\vec{E} = 1800\ N/C$ (towards)

Now, at x = 1 cm = 0.01 m :

Using eqn (1):

$\vec{E'} = \frac{2\times 9\times 10^{9}\times - 1\times 10^{- 9}}{0.01} = - 1800\ N/C$

$\vec{E'} = 1800\ N/C$ (towards)

Now, the total field at the origin is the sum of both the fields:

$\vec{E_{net}} = 1800 + 1800 = 3600\ N/C$

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3 years ago

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Isaac Newton’s second law of motion

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3 years ago

A rock is thrown down with an initial speed of 25.3 m/s from a bridge to the water below. It takes 2.29 s for the rock to hit th

Rzqust [24]

<h2>Height of bridge is 83.66 m</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

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Time, t = 2.29 s

Substituting

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s = 25.3 x 2.29 + 0.5 x 9.81 x 2.29²

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3 years ago