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2 years ago

Which description of the graph of y = 500x is most accurate?

1 answer:

6 0

Answer: .The graph is a line that rises steeply from left to right and passes through the origin. 2.The graph is a line that rises gradually

Step-by-step explanation: hope tha help

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F(x)=-1/2(x-2)^2-4 <br> Graph the function

telo118 [61]

Answer:

see below

Step-by-step explanation:

The function is written in vertex form. It has a negative vertical scale factor, so you know ...

the vertex is (2, -4)
the vertical scale factor is 1/2
the parabola opens downward

Vertex form is ...

f(x) = a(x -h)^2 +k . . . . . . . . . . vertical scale factor "a", vertex (h, k)

Since you know the vertex and scale factor, you can plot some points on the graph. I find it convenient to think in terms of units either side of the vertex. These are values of x that would make (x-2)^2 be 1^2, 2^2, 3^2, 4^2 and so on. The vertical scale factor of -1/2 tells you that the y-differences for these points will be -1/2, -4/2, -9/2, -16/2 from the vertex. Then we have ...

vertex: (2, -4)

1 unit either side of the vertex: (1, -4.5), (3, -4.5)

2 units either side of the vertex: (0, -6), (4, -6)

3 units either side of the vertex: (-1, -8.5), (5, -8.5)

4 units either side of the vertex: (-2, -12), (6, -12)

You can plot these points and draw a smooth curve through them. Or, you can let a graphing calculator do it. The result will be similar to that shown below.

6 0

3 years ago

ERRE

Karo-lina-s [1.5K]

y-5

2y+ 1

y-5

6y+7

y-5

2y+5

y-5

6y+ 7

-2y-10

2y+5

-2y-10

3 0

3 years ago

A cookie has 130 calories.

pychu [463]

I think the answer would be B

5 0

3 years ago

A piece of wire of length 6363 is cut, and the resulting two pieces are formed to make a circle and a square. Where should the

Lerok [7]

Answer:

35.2792 cm from one end (The square)

And 27.7208 cm from the other end (The circle)

b. See (b) explanation below

Step-by-step explanation:

Given

Length of Wire ,= 63cm

Let L be the length of one side of the square

Circumference of a circle = 2πr

Perimeter of a square = 4L

a. To minimise

4L + 2πr = 63 ----- make r the subject of formula

2πr = 63 - 4L

r = (63 - 4L)/2π

r = (31.5 - 2L)/π

Let X = Area of the Square. + Area of the circle

X = L² + πr²

Substitute (31.5 - 2L)/π for r

So,

X² = L² + π((31.5 - 2L)/π)²

X² = L² + π(31.5 - 2L)²/π²

X² = L² + (31.5 - 2L)²/π

X² = L² + (992.25 - 126L + 4L²)/π

X² = L² + 992.25/π - 126L/π +4L²/π ------ Collect Like Terms

X² = 992.25/π - 126L/π + 4L²/π + L²

X² = 992.25/π - 126L/π (4/π + 1)L² ---- Arrange in descending order of power

X² = (4/π + 1)L² - 126L/π + 992.25/π

The coefficient of L² is positive so this represents a parabola that opens upward, so its vertex will be at a minimum

To find the x-cordinate of the vertex, we use the vertex formula

i.e

L = -b/2a

L = - (-126/π) / (2 * (4/π + 1)

L = (126/π) / ( 2 * (4 + π)/π)

L = (126/π) /( (8 + 2π)/π)

L = 126/π * π/(8 + 2π)

L = (126)/(8 + 2π)

L = 63/(4 + π)

So, for the minimum area, the side of a square will be 63/(4 + π)

= 8.8198 cm ---- Approximated

We will need to cut the wire at 4 times the side of the square. (i.e. the four sides of the square)

I.e.

4 * (63/(4 + π)) cm

35.2792 cm from one end.

Subtract this result from 63, we'll get the other end.

i.e. 63 - 35.2792

= 27.7208 cm from the other end

b. To maximize

Now for the maximum area.

The problem is only defined for 0 ≤ L ≤ 63/4 which gives

0 ≤ L ≤ 15.75

When L=0, the square shrinks to 0 and the whole 63 cm wire is made into a circle.

Similarly, when L =15.75 cm, the whole 63 cm wire is made into a square, the circle shrinks to 0.

Since the parabola opens upward, the maximum value is at one endpoint of the interval, either when

L=0 or when L = 15.75.

It is well known that if a piece of wire is bent into a circle or a square, the circle will have more area, so we will assume that the maximum area would be when we "cut" the wire 0, or no, centimeters from the

end, and bend the whole wire into a circle. That is we don't cut the wire at

all.

7 0

2 years ago

30 points! Find the four arithmetic means between -17 and 32.

bearhunter [10]

Answer: - 7.2 , 2.6 , 12.4 and 22.2

Step-by-step explanation:

Let the arithmetic means be p , q , r ,s , therefore , the sequence becomes:

-17 , p , q , r , s , 32

The first term (a ) = -17

Last term (L) = 32

common difference (d) = ?

number of terms (n ) = 6

We will use the formula for calculating the last term to find the common difference. That is

L = a + (n - 1 ) d

Substituting the values , we have

32 = -17 + (6-1) d

32 = -17 + 5d

32 + 17 = 5d

49 = 5d

Therefore: d = 9.8

We can therefore find the values of p , q , r , and s

p is the second term , that is

p = a + d

p = -17 + 9.8

p = -7.2

q = a + 2d

q = - 17 + 19.6

q = 2.6

r = a + 3d

r = - 17 + 29.4

r = 12.4

s = a + 4d

s = - 17 + 39.2

s = 22.2

Therefore : the arithmetic means are : - 7.2 , 2.6 , 12.4 and 22.2

8 0

3 years ago