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2 years ago

8: Harry is 3 years older and Andy is twice as old as

Mathematics

2 answers:

White raven [17]2 years ago

7 0

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nikitadnepr [17]2 years ago

4 0

Step-by-step explanation:

given,

Harry = 3yrs

Andy = 2x ( twice as old as sam )

sam = x

their sum = 27

a/q

→ 2x + x + 3 = 27

→ 3x = 27 - 3 = 24

→ x = 24/3 = 8

→ x = 8

therefore, age of sam is 8 and Andy is 16 and Harry is 3.

the equation is

2x + x + 3 = 27

hope this answer helps you..and may u have a great day ahead!

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An electrician bent a section of copper wire into a partial circle as shown. The dimensions are

ira [324]

Answer:

Length = 3.84 feets (nearest hundredth)

Step-by-step explanation:

The length of section of wire can be obtyaiejd using the length of of a arc formular :

Length of arc = θ/360° * 2πr

Radius, r = 2.5 feets

Length of arc = (88/360) *2πr

Length of arc = (88/360) * 2π*2.5

Length of arc = 0.244444 * 15.707963

Length of arc = 3.8397

Length = 3.84 feets (nearest hundredth)

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2 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

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2 years ago

The arrow on the spinner is to be spun once. What is the probability that the arrow will stop on 2? A.1/2 B.1/3 C.1/4 D.1/6

lara31 [8.8K]

How many numbers are on there? And how many times does 2 appear on the spinner?

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3 years ago

The figure is made up of two shapes, a semicircle and a rectangle.What is the exact perimeter of the figure?

grandymaker [24]

Perimeter of circular area = πr = 3.14 * 10 = 31.4 mm

Perimeter of rectangular area = 30 + 20 + 30 = 80 mm

Total Perimeter = 80 + 31.4 = 111.4

In short, Your Answer would be 111.4 mm

Hope this helps!

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