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3 years ago

10

Electrons determine the of an atom

1 answer:

g100num [7]3 years ago

7 0

Answer:

if u know the number of electrons u also know the number of protons present in the atom.

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Why is there little heat retained in the warm thermosphere? a. The pressure is too low c. The molecules move too fast b. The pre

iren [92.7K]

I believe the correct answer is A

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4 years ago

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Which of the following gases would be most likely to experience ideal behavior at high pressures?

monitta

<span>Which of the following gases would be most likely to experience ideal behavior at high pressures?
a. F2
b. Ne
c. C2H6

Yes. The answer is (b) Ne (Neon). This is because monoatomic gases such as neon do not experience </span><span>intermolecular attractions and thus most likely to be close to ideal gases behavior. Not only that, Neon is a noble gas and is unreactive. </span>

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4 years ago

Use the following equation to answer the questions and please show all work.

DIA [1.3K]

Answer:

a.36 g of water is produced.

b.64 g of $O_{2}$ is consumed.

Explanation:

The reaction is $2H_{2} + O_{2}$ ⇒ $2H_{2}O$

a.

Given,

Weight of $H_{2}$ reacted = 4g

Weight of 1 mole of $H_{2}$ = 2 $\times$ 1 = 2g

Therefore no. of moles of $H_{2}$ reacted = $\frac{4}{2}$ = 2 moles;

Also given,

Weight of $O_{2}$ reacted = 32 g

Weight of 1 mole of $O_{2}$ = 2 $\times$ 16 = 32 g

Therefore no. of moles of $O_{2}$ reacted = $\frac{32}{32}$ = 1

We know that 2 moles of Hydrogen reacts with 1 mole of Oxygen to give 2 moles of water,

As we took 2 moles of Hydrogen and 1 mole of Oxygen,

Directly,from the equation we can tell 2moles of water will be produced.

Therefore no. of moles of $H_{2} O$ produced = 2

Weight of 1 mole of water = $2\times 1+16$ = 18

Therefore weight of $H_{2}O$ produced = $2\times 18$ = 36gm

b.

Given ,

72 g of $H_{2}O$ is produced.

So,

no. of moles of $H_{2}O$ produced = $\frac{72}{18}$ = 4 moles

From equation For every 2 moles of water formed , 1 mole of oxygen must be required.

So for producing 4 moles of water,

No. of moles of Oxygen required = 2 moles.

Therefore weight of $O_{2}$ reacted = $2\times32$ = 64 g

Method 2:

Given,

8 g of $H_{2}$ has reacted.

So,

no. of moles of $H_{2}$ reacted = $\frac{8}{2}$ = 4 moles.

From equation , we know that For every 2 moles of $H_{2}$ reacted,1 mole of $O_{2}$ will react.

Therefore,

No. of moles of $O_{2}$ that reacts with 4 moles of $H_{2}$ = $2\times1$ = 2 moles

Therefore the weight of $O_{2}$ reacted = $2\times 32$ = 64 g

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3 years ago

What happens when you rub a plastic ruler and bring it closer to the tissue bits

morpeh [17]

Explanation:

When you rub a plastic ruler and bring it closer to a tissue, the piece of tissue is forced to attach to the ruler because of some electricity.

6 0

3 years ago

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A sample of gas has a mass of 827 mg . Its volume is 0.270 L at a temperature of 88 ∘ C and a pressure of 975 mmHg . Find its mo

Anuta_ua [19.1K]

Steps:

Mw = w * R * T / p * V

T = 88 + 273 => 361 K

p = 975 mmHg in atm :

1 atm = 760 mmHg

975 mmg / 760 mmHg => 1.28 atm

Therefore:

= 0.827 * 0.0821 * 361 / 1.28 * 0.270

= 24.51 / 0.3456

molar mass = 70.92 g/mol

8 0

4 years ago

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