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12345 [234]
3 years ago
10

How many liters of 0.37 M solution can be made with 29.53 grams of lithium fluoride. (LiF)?

Chemistry
1 answer:
dsp733 years ago
4 0

Answer:

V = 3.1 L      

Explanation:

Given data:

Molarity of solution = 0.37 M

Mass of LiF = 29.53 g

Volume of solution = ?

Solution:

Number of moles of LiF:

Number of moles = mass/molar mass

Number of moles = 29.53 g/ 25.94g/mol

Number of moles = 1.14 mol

Volume:

Molarity = number of moles of solute / Volume in L

0.37 M = 1.14 mol / V

V = 1.14 mol / 0.37 M

V = 3.1 L         (M = mol/L)

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Why are the temperatures on other objects in the solar system more extreme than the temperatures on the Earth?
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Give an example of how you could use different reference frames for the same motion.
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Write the balanced molecular chemical equation for the reaction
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The balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

  • For any chemical equation to be balanced, the number of moles of elements in the reactants must be equal to that of the product.

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  • The chemical formula for Cesium carbonate is Cs₂CO₃
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Calculate the amount of water required to prepare 500g of 2.5% solution of sugar.
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(i) We start by calculating the mass of sugar in the solution:

mass of sugar = concentration × solution mass

mass of sugar = 2.5/100 × 500 = 12.5 g  

Then now we can calculate the amount of water:

solution mass = mass of sugar + mass of water

mass of water =  solution mass - mass of sugar

mass of water = 500 - 12.5 = 487.5 g

(ii) We use the following reasoning:

If       500 g solution contains 12.5 g sugar

Then    X g solution contains 75 g sugar

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Density = mass / volume

Volume = mass / density

Volume = 3000 / 1 = 3000 liters of sugar solution

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