How many liters of 0.37 M solution can be made with 29.53 grams of lithium fluoride. (LiF)?

Chemistry

1 answer:

dsp733 years ago

4 0

Answer:

V = 3.1 L

Explanation:

Given data:

Molarity of solution = 0.37 M

Mass of LiF = 29.53 g

Volume of solution = ?

Solution:

Number of moles of LiF:

Number of moles = mass/molar mass

Number of moles = 29.53 g/ 25.94g/mol

Number of moles = 1.14 mol

Volume:

Molarity = number of moles of solute / Volume in L

0.37 M = 1.14 mol / V

V = 1.14 mol / 0.37 M

V = 3.1 L (M = mol/L)

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