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GarryVolchara [31]
3 years ago
8

If you are standing and not moving, which statement is true? You are experiencing an unbalanced force. The normal force is great

er than your weight. your weight and mass are the same. Normal force is equal to your weight​
Physics
1 answer:
viktelen [127]3 years ago
4 0
What’s the question, but your a k pop stan hi
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Suppose that the oil in a hydraulic hoist is replaced by air. Would the hoist still operate as well? Explain.
shtirl [24]
No


The object/objects inside would have to be of a certain consistency/element/form so air wouldn’t work
7 0
3 years ago
A 1-kg plastic block is neutrally buoyant when submerged in water with a density of 1 g/cm3. If the same block is placed, such t
goldenfox [79]

Answer:

-2 m/s

Explanation:

The computation of the acceleration of the block is as follows:

The volume of the block is

V = 1kg ÷ 1,000 kg/m^3 = 1 ÷ 1,000 m^3

Now at the time of submerging in the oil

Net force is

m_g - F_B = m \times (-a)\\\\m_g - v\times S_{oil} \times g = -ma\\\\a = (\frac{v}{m} \times S_{oil}  - 1) g\\\\= (\frac{1}{1000} \times 0.8 \times 1000 -1 ) \times 10\\\\

= -2 m/s

8 0
3 years ago
When you have a pot of water on the stove, heat is transferred to the water. Describe the behavior of the water molecules and ho
NikAS [45]
<span>Temperature causes water molecules to move more quickly, because each individual molecule has more energy as it gets hotter (according to Kinetic molecular theory). If you get water hot enough, the molecules move so much that the hydrogen bonds that hold them together start to break and the water becomes a gas ... water vapor. This your answer unless there are choices.</span>
3 0
4 years ago
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How to make a force field for your house
Lelu [443]
That is not yet possible. that technology has not yet been invented.
6 0
3 years ago
You place a piece of aluminum at 250.0∘C ∘ C in 9.00 kg k g of liquid water at 20.0∘C ∘ C . None of the water boils, and the fin
Mice21 [21]

Answer:

m₁ = 0.37 kg

Explanation:

According to Law of conservation of energy:

Heat Lost by Aluminum = Heat Gained by Water

m₁C₁ΔT₁ = m₂C₂ΔT₂

where,

m₁ = mass of piece of aluminum = ?

C₁ = specific heat capacity of aluminum = 900 J/kg.°C

ΔT₁ = Change in temperature of aluminum = 250°C - 22°C = 228°C

m₂ = mass of water = 9 kg

C₂ = specific heat capacity of water = 4200 J/kg.°C

ΔT₁ = Change in temperature of aluminum = 22°C - 20°C = 2°C

Therefore,

m₁(900 J/kg.°C)(228 °C) = (9 kg)(4200 J/kg.°C)(2°C)

m₁ = (75600 J)/(205200 J/kg)

<u>m₁ = 0.37 kg</u>

5 0
3 years ago
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