Answer:
Explanation:
When a camera shifts focus from a faraway object to a nearby object, the lens-to-film distance must increase. Likewise, when it shifts focus from a nearby object to a distant object, there must be an increase in the lens to film distance (that is, the image distance).
Therefore, if the picture of an object that is far away, the lens must move towards the film.
The focal length cannot be changed because it is fixed for a lens. Nevertheless, in order to focus on an object, the image distance can be changed.
Answer:
51.94 ft/s²
257.63 ft/s
Explanation:
t = Time taken = 4 s
u = Initial velocity = 34 mi/h
v = Final velocity
s = Displacement = 615 ft
a = Acceleration
Converting velocity to ft/s
Equation of motion
Acceleration is 51.94 ft/s²
Final velocity at this time is 257.63 ft/s
Answer:
30 metres.
Explanation:
Given that a red ball moves horizontally in a 30 m long tube.
Displacement is the distance travelled in a specific direction. It has both magnitude and direction.
Since the motion is horizontal, it moves is a certain direction.
Within the stipulation of time, the displacement will be the distance covered in the horizontal direction which is 30 metres.
Therefore, the displacement of the motion of the red ball is 30 metres.
