The film sensor and the long axis of the tooth must be aligned perpendicular to the central ray of the x-ray beam when using the paralleling approach.
To find the answer, we need to know above the paralleling technique in the dental x-ray.
<h3>What is paralleling technique?</h3>
- The paralleling technique is the most dependable method for capturing periapical x-rays because it produces high-quality images with little distortion.
- The central x-ray beam should be pointed perpendicular to the long axis of the tooth in issue, and the film should be positioned parallel to it.
- The paralleling technique is the most dependable method for capturing periapical x-rays because it produces high-quality images with little distortion.
- The central x-ray beam should be pointed perpendicular to the long axis of the tooth in issue, and the film should be positioned parallel to it.
- When preparing for an x-ray, it is imperative to keep in mind the root anatomy.
- The maxillary occlusal plane of the patient should also be parallel to the ground.
Thus, we can conclude that, the film sensor and the long axis of the tooth must be aligned perpendicular to the central ray of the x-ray beam when using the paralleling approach.
Learn more about paralleling technique here:
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Answer with Explanation:
We are given that
Electric field vector=
Magnetic field vector=
We have to find the direction of propagation of the wave.
We know that
The direction of propagation of wave=
The direction of propagation of wave=
Because (
)
The wave propagate in -z direction.
Therefore, the component of the vector is (0,0,-1).
Hence, the direction of the propagation of wave is - z direction and component of direction of propagation vector is (0,0,-1).
Answer:
(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz
(b) 250 m/s
(c) 1250 N
(d) Positive x-direction
(e) 6.00 m/s
(f) 0.0365 m
Explanation:
(a) The standard form of the wave is:
y = A cos ((2πf) t ± (2π/λ) x)
where A is the amplitude, f is the frequency, and λ is the wavelength.
If the x term has a positive coefficient, the wave moves to the left.
If the x term has a negative coefficient, the wave moves to the right.
Therefore:
A = 0.0800 m
2π/λ = 0.300 m⁻¹
λ = 20.9 m
2πf = 75.0 rad/s
f = 11.9 Hz
(b) Velocity is wavelength times frequency.
v = λf
v = (20.9 m) (11.9 Hz)
v = 250 m/s
(c) The tension is:
T = v²ρ
where ρ is the mass per unit length.
T = (250 m/s)² (0.0200 kg/m)
T = 1250 N
(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).
(e) The maximum transverse speed is Aω.
(0.0800 m) (75.0 rad/s)
6.00 m/s
(f) Plug in the values and find y.
y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))
y = 0.0365 m
Answer:
Total energy =kinetic energy +potential energy.
Answer:
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