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2 years ago

The table describes the properties of four compounds.

Physics

2 answers:

irga5000 [103]2 years ago

8 0

Answer:

compounds C and D

Explanation:

I believe this is correct

earnstyle [38]2 years ago

8 0

Mark the last person brainliest please

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(Figure 1) shows the angular-velocity-versus-time graph for a particle moving in a circle. How many revolutions does the object

Travka [436]

Answer: 10.34

Explanation:

Given

$\omega -t$ graph for a particle is given

angle turned by the particle in radians is given by the area under $\omega -t$ graph

The area is given by

$A=20\times (2-0)+10(4-2)+\dfrac{1}{2}\times (20-10)\times (3-2)\\A=40+20+5=65\ rad$

Revolutions(N) made by the object is given by

$N=\dfrac{65}{2\pi }=10.34$

4 0

2 years ago

A helicopter starting on the ground is rising directly into the air at a rate of 25 ft/s. You are running on the ground starting

rusak2 [61]

Answer:

The rate of change of the distance between the helicopter and yourself (in ft/s) after 5 s is $\sqrt{725}$ ft/ sec

Explanation:

Given:

h(t) = 25 ft/sec

x(t) = 10 ft/ sec

h(5) = 25 ft/sec . 5 = 125 ft

x(5) = 10 ft/sec . 5 = 50 ft

Now we can calculate the distance between the person and the helicopter by using the Pythagorean theorem

$D(t) = \sqrt{h^2 + x^2}$

Lets find the derivative of distance with respect to time

$\frac{dD}{dt} (t) = \frac{2h \cdot \frac{dh}{dt} +2x \cdot\frac{dx}{dt}} {2\sqrt{h^2 + x^2}}$

Substituting the values of h(t) and x(t) and simplifying we get,

$\frac{dD}{dt}(t) = \frac{50t \cdot \frac{dh}{dt} + 20 \cdot \frac{dx}dt}{2\sqrt{625\cdot t^2 + 100 \cdot t^2}}$

$\frac{dh}{dt} = 25ft/sec$

$\frac{dx}{dt} = 10 ft/sec$

$\frac{Dd}{dt} (t) = \frac{1250t +200t}{2\sqrt{725}t}$ = $\frac{725}{\sqrt{725}}$ = $\sqrt{725}$ ft / sec

5 0

3 years ago

Any help would be great! Thank you x<br><br><br> Giving brainliest answer xoxo

garri49 [273]

Answer:

A vacuum would have been created. I hope this helps have a great day

3 0

3 years ago

31. Draw a free body diagram for a 15.5N box that is being pushed to the right with a 18. N force while experiencing 4.30 N of r

posledela

Answer:

See answers below

Explanation:

F = mg,

15.5 N = m(9.8 m/s²)

m = 1.58 kg

Fnet = Applied force - resistance,

Fnet = 18 N - 4.30 N,

Fnet = 13.70 N

Fnet = ma

13.70 N = (1.58 kg)a

a = 8.67 m/s²

For the free body diagram, draw a box with an upward arrow labeled 15.5 N, a downward label labeled 15.5 N, a right label labeled 18 N, and a left label labeled 4.30 N.

7 0

2 years ago

zhannawk [14.2K]

Average speed= total distance/total time =12km/h

6 0

3 years ago