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yan [13]
2 years ago
9

The table describes the properties of four compounds.

Physics
2 answers:
irga5000 [103]2 years ago
8 0

Answer:

compounds C and D

Explanation:

I believe this is correct

earnstyle [38]2 years ago
8 0
Mark the last person brainliest please
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To calculate how much rest energy an object contains, you multiply
Rina8888 [55]
This is what e=mc² means.
So rest energy is RH side of equation that is its mass times speed of light squared.
5 0
3 years ago
Which of the following statements is correct? Which of the following statements is correct? The more a muscle shortens, the more
NeX [460]

The correct answer are

a)  "The number of muscle fibers best determines how powerful a muscle will be"

b) "The more a muscle shortens, the more power it generates."

Reason :

Muscle fiber in longitudinal directions generate more power

Multipennate muscles do not produce much power because the tendon branches within muscle .



4 0
3 years ago
Show your workikkkkkkkk
Svet_ta [14]

Answer:

Explanation:

F = ma

<u>Assuming</u> the 20° is angle θ measured to the horizontal

mgsinθ - μmgcosθ = ma

g(sinθ - μcosθ) = a

at constant velocity, a = 0

g(sinθ - μcosθ) = 0

   sinθ - μcosθ = 0

                 sinθ = μcosθ

μ = sinθ/cosθ

μ = tanθ

μ = tan20

μ = 0.3639702342...

μ = 0.36

6 0
2 years ago
A 3kg box has 45J of gravitational potential energy, how high is it off the ground?
frez [133]

Answer:

1.53m

Explanation:

Given parameters:

Mass of box  = 3kg

Gravitational potential energy  = 45J

Unknown

Height of the box  = ?

Solution:

To solve this problem;

 Gravitational potential energy = mgh

m is the mass

g is the acceleration due to gravity

h is the height

            45  = 3 x 9.8 x h

            h  = 1.53m

7 0
3 years ago
An 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching th
ddd [48]

Answer:

1626.4 N

Explanation:

Given that a 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. What force does the water exert on him?

The parameters to be considered are:

Distance S = 3m

Time t = 0.55s

Since the man started from rest, initial velocity u = 0

Using second equation of motion

S = Ut + 1/2at^2

3 = 1/2 × a × 0.55^2

3 = 1/2 × a × 0.3025

a = 3/ 0.15125

a = 19.83 m/s^2

Force = mass × acceleration

Force = 82 × 19.83

Force = 1626.4 N

Therefore, the force that water exerted on him is 1626.4 N

4 0
3 years ago
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