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3 years ago

Differentiate between low pitch and high pitch

Physics

2 answers:

stich3 [128]3 years ago

7 0

You can hear a difference between these two sounds. That is because their pitch is different. Pitch depends on the frequency of a sound wave. ... High sounds have high frequencies and low sounds have low frequencies.

alexdok [17]3 years ago

6 0

Pitch depends on the frequency of a sound wave. High sounds have high frequencies and low sounds have low frequencies.

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PLS ANSWER ASAP

TiliK225 [7]

Answer: Answer is D

I took the test little while back.

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3 years ago

Question 11

notka56 [123]

The volume of the gas once it reaches the surface of water is 2 liters.

The volume of the air in balloon at depth of 100ft (30m) is 500ml.

The pressure at this point is 4 atm.

Assuming that the balloon have no compression by rubber of balloon the volume of air at the water surface is V.

The pressure at the surface of water is 1 atms.

As we know, from the ideal gas equation,

PV = nRT

Where,

P is the Pressure of gas,

V is the volume of the gas,

n is the number of moles,

R is the gas constant whose value is 0.082057 L atm mol-1 K-1,

T is the temperature.

Assuming that the temperature is constant,

We know,

PV = nRT

All quantities on the right side are constants,

So, we can write,

P₁V₁ = P₂V₂

Putting all the the values,

4(0.5) = 1V₂

V₂ = 2 Liters.

The volume of the air at the surface is 2 liters.

1 liter = 0.001 m

Hence,

2 liters = 0.002 m³

So the volume of air at the surface is 0.002m³.

To know more about Ideal gas Equation, visit,

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3 0

1 year ago

A force sets an object in motion when the force is multiplied

pickupchik [31]

A force sets an object in motion when the force is multiplied by the time of its application.

4 0

3 years ago

Find the fundamental frequency and the next three frequencies that could cause standing-wave patterns on a string that is 30.0 m

maksim [4K]

Answer:

0.786 Hz, 1.572 Hz, 2.358 Hz, 3.144 Hz

Explanation:

The fundamental frequency of a standing wave on a string is given by

$f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}$

where

L is the length of the string

T is the tension in the string

$\mu$ is the mass per unit length

For the string in the problem,

L = 30.0 m

$\mu=9.00\cdot 10^{-3} kg/m$

T = 20.0 N

Substituting into the equation, we find the fundamental frequency:

$f=\frac{1}{2(30.0)}\sqrt{\frac{20.0}{(9.00\cdot 10^{-3}}}=0.786 Hz$

The next frequencies (harmonics) are given by

$f_n = nf$

with n being an integer number and f being the fundamental frequency.

So we get:

$f_2 = 2 (0.786 Hz)=1.572 Hz$

$f_3 = 3 (0.786 Hz)=2.358 Hz$

$f_4 = 4 (0.786 Hz)=3.144 Hz$

6 0

4 years ago

If a cannonball is fired horizontally it will not go in a straight line why?

goldfiish [28.3K]

Explanation:

A projectile (Cannon ball) is launched at an angle to the horizontal and rises up to a peak while moving horizontally. When it reaches the peak, the projectile starts to fall.

5 0

2 years ago