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defon
3 years ago
10

A person runs at a speed of 4 meters per second. How far will the person travel in 40 seconds?

Physics
1 answer:
NARA [144]3 years ago
5 0
To determine the distance (d) traveled by a body given its speed (S) and the time (t). Use the equation,
 
                             S = d / t           ;          d = S x t

Substituting the known values to the equation,
 
                                      d = (4 m/s ) x (40 s) = 160 m

Thus, the person will travel 160 meters in 40 seconds. 
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The Heavier Firefighter

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Why do astronomers use the word on to describe angles on the sky rather than angles in the sky?
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During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 * t2 to so
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Read 2 more answers
A small economy car (low mass) and a limousine (high mass) are pushed from rest across a parking lot, equal distances with equal
Studentka2010 [4]

Answer:

The car that receives more kinetic energy is the small economy car.

Explanation:

K.E = 0.5*mv²

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K.E is the kinetic Energy

M is the mass of an object

V is the velocity of the moving object

But F = m(v/t), from Newton's second law of motion

If equal forces were applied to the two cars, then the velocity of each car will be calculated as follows.

v = (Ft/m)

v² = (Ft/m)²

Substitute in the value of v² into Kinetic energy equation

K.E = 0.5*mv²

K.E = 0.5*m(Ft/m)² = (0.5*F²t²)/m

Also assuming equal distance, equal force and assuming equal time for both cars.

The above equation will reduce to, K.E = k/m

Where k = 0.5*F²t², which is equal in both cars.

Thus, Kinetic energy will depend only on the mass of each car.

From the above expression, Kinetic Energy received by each car is inversely proportional to the mass of the car.

A small economy car (low mass)  will receive more kinetic energy while a limousine (high mass) car will receive less kinetic energy.

Therefore, the car that receives more kinetic energy is the small economy car.

6 0
3 years ago
The mass of a string is 5.9 × 10-3 kg, and it is stretched so that the tension in it is 200 n. a transverse wave traveling on th
bagirrra123 [75]

The velocity of the wave on the string is given by

v=\sqrt{\frac{T}{\frac{m}{L}}}  \\  v=\sqrt{\frac{TL}{m}}

Solving the above equation,

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Substituting numerical values,

L=\frac{228^2(0.0059)}{200}\\ T=1.534

The length of the string is 1.534 m

4 0
3 years ago
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