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tatiyna
3 years ago
6

What is the distance between two spheres (20 kg and 30 kg) attracted by a force of 2 x 10^-5 Newtons.

Physics
1 answer:
creativ13 [48]3 years ago
6 0
2 times 10 to the power of 5 is your answer.
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The angular momentum of a flywheel having a rotational inertia of 0.140 kg ·m2 about its central axis decreases from 3.00 to 0.8
Rasek [7]

Answer

given,

I = 0.140 kg ·m²

decrease from 3.00 to 0.800 kg ·m²/s in 1.50 s.

a) \tau = \dfrac{\Delta L}{\Delta t}

   \tau = \dfrac{0.8-3}{1.5}

        τ = -1.467 N m

b) angle at which fly wheel will turn

   \theta= \omega t +\dfrac{1}{2}\alpha t^2

   \theta= \dfrac{L}{I} t +\dfrac{1}{2}\dfrac{\tau}{I}t^2

   \theta= \dfrac{3}{0.14}\times 1.5+\dfrac{1}{2}\dfrac{-1.467}{0.14}\times 1.5^2

        θ = 20.35 rad

c) work done on the wheel

     W = τ x θ

     W = -1.467 x 20.35 rad

    W = -29.86 J

d) average power of wheel

    P_{av} =-\dfrac{W}{t}

    P_{av} =-\dfrac{(-29.86)}{1.5}

     P_{av} =19.91\ W          

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3 years ago
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Taden has found a table of the atmospheric layers of the Sun. However, he can’t make out the names of the layers in the chart.
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The sun is a ball of hot gases containing different kinds of elements at different cores. It has a very high temperature that radiates all throughout the Milky Way galaxy. The sun has three main parts; photosphere, chromospheres and corona. The outer core of a star located at the chromospheres contains mostly of hydrogen. Inside the hydrogen is helium then carbon, oxygen, neon, magnesium silicon and the inert gas. The photosphere is scattered by the loose electrons in the corona’s plasma.

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Which action might lead scientists to develop new explanations about the
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vrzjxuxuxjcckhcouvou

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gghhjjokjjhghhrjxjxkyxygbjv

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A __ allows you to determine the position of an object <br><br>this is science plz helpp​
Alex_Xolod [135]
The correct answer is C
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What fraction of the total energy of a SHO is kinetic when the displacement is one third the amplitude
Bas_tet [7]

Answer:

The fraction of kinetic energy to the total energy is \frac{K}{T}=\frac{8}{9}.

Explanation:

displacement is one third of the amplitude.

Let the amplitude is A.

x= A/3

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K = 0.5 mw^2(A^2 - x^2)\\\\K = 0.5 m w^2 \left ( A^2 -\frac{A^2}{9} \right )\\\\K = 0.5 mw^2\times \frac{8A^2}{9}......(1)

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