Answer:
He is a English chemist physicist and meteorologist. He is best known for the atomic theory 
 
        
             
        
        
        
Answer:
1).....for the specific heat capacity(c) of water is 4200kg/J°C..
....guven mass(m)=320g(0.32kg)
...change in temperature(ΔT) =35°C
from the formula
 Q=mcΔT
Q=0.32Kg x 4200kg/J°C x 35°C
Q=47,040Joules
 
        
             
        
        
        
Answer:
(a) 6.38 × 10⁻²⁹ kg·m·s⁻¹; (b) 7.00 kg·m·s⁻¹; (c) 82.7 µm; (d) 7.53 × 10⁻³⁴  m;
(e) Δx ∝ 1/m
Explanation:
(a) Momentum of electron
p = mv = 9.11  × 10⁻³¹ kg × 70.0 m·s⁻¹ = 6.38 × 10⁻²⁹ kg·m·s⁻¹
(b) Momentum of tennis ball
p = mv = 0.1000 kg × 70.0 m·s⁻¹ = 7.00 kg·m·s⁻¹
(c) Δx for electron
Δp = 0.010p = 0.010 × 6.38 × 10⁻²⁹ kg·m·s⁻¹ = 6.38 × 10⁻³¹ kg·m·s⁻¹

(d) Δx for tennis ball
Δp = 0.010p = 0.010 × 7.00 kg·m·s⁻¹ = 0.0700 kg·m·s⁻¹

(e) Relative uncertainty
Both particles are travelling at the same speed, so,
ΔxΔp = Δx × mv = mvΔx = constant
v is constant, so  
Δx ∝ 1/m
Thus, the larger the mass of an object, the smaller the uncertainty in its velocity.
 
        
             
        
        
        
Coal-fire power plants.
I hope this helps ya!
        
             
        
        
        
Answer:
Your strategy here will be to use the molar mass of potassium bromide, 
KBr
 , as a conversion factor to help you find the mass of three moles of this compound.
So, a compound's molar mass essentially tells you the mass of one mole of said compound. Now, let's assume that you only have a periodic table to work with here.
Potassium bromide is an ionic compound that is made up of potassium cations, 
K
+
 , and bromide anions, 
Br
−
 . Essentially, one formula unit of potassium bromide contains a potassium atom and a bromine atom.
Use the periodic table to find the molar masses of these two elements. You will find
For K: 
M
M
=
39.0963 g mol
−
1
 
For Br: 
M
M
=
79.904 g mol
−
1
 
To get the molar mass of one formula unit of potassium bromide, add the molar masses of the two elements
M
M KBr
=
39.0963 g mol
−
1
+
79.904 g mol
−
1
≈
119 g mol
−
So, if one mole of potassium bromide has a mas of 
119 g
 m it follows that three moles will have a mass of
3
moles KBr
⋅
molar mass of KBr
119 g
1
mole KBr
=
357 g
 
You should round this off to one sig fig, since that is how many sig figs you have for the number of moles of potassium bromide, but I'll leave it rounded to two sig figs
mass of 3 moles of KBr
=
∣
∣
∣
∣
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
360 g
a
a
∣
∣
−−−−−−−−−
Explanation:
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