All categories

3 years ago

2 Points

Chemistry

1 answer:

lara [203]3 years ago

3 0

Answer:

All colors except blue are absorbed while blue is reflected. We

only see blue

Explanation:

When you go and see something blue as the sky, all of the colors are absorbed except blue. That is how we see colors

You might be interested in

Are any other answer correct ? ♈❤️

riadik2000 [5.3K]

Those two are correct, your just missing A.

6 0

2 years ago

Read 2 more answers

What is the formula (with cation and anion charges) for copper (II) hydroxide?

Thepotemich [5.8K]

Answer:

Cu²⁺(OH)⁻₂

Explanation:

Step 1: Find the symbols for the substances

For copper, see your periodic table. Copper is "Cu".

For hydroxide, see your polyatomic ions chart. Hydroxide is "OH".

Step 2: Find the charges for each element.

Copper (II)'s charge is 2, which is the roman numerals in the brackets.

Hydroxide's charge is -1.

Charges are written as superscripts. You do not need to write "1".

In formulas, write the positively charged atom first.

Cu²⁺(OH)⁻ Put brackets around hydroxide because it has 2 elements.

Step 3: Write the number of atoms.

The number of atoms that an element has is the same as its partner's charge.

The charge of copper is 2, so hydroxide has 2 atoms.

The charge of hydroxide is 1, so copper has 1 atom.

Cu²⁺₁(OH)⁻₂

You do not need to write the "1" for atoms.

Cu²⁺(OH)⁻₂

8 0

2 years ago

What is the frequency of a photon with an energy of 3.26 x 10-19 J?

Kobotan [32]

Answer:

$from \: eisteins \: energy \: relation : \\ E = hf \\ h \: is \: plancks \: constant\\ 3.26 \times {10}^{ - 19} = 6.63 \times {10}^{ - 34 } \times f \\ f = \frac{3.26 \times {10}^{ - 19} }{6.63 \times {10}^{ - 34} } \\ f = 4.92 \times {10}^{14} \: Hz$

8 0

2 years ago

If a particular ore contains 58.6 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp

rjkz [21]

Answer is: mass of the ore is 8.54kg.

ω(Ca₃(PO₄)₂ - calcium phosphate) = 58.6% ÷ 100% = 0.586.
m(P) = 1.00 kg · 1000 g/kg.
m(P) = 1000 g.
In one molecule of calcium phosphate there are two phosphorus atoms:
M(Ca₃(PO₄)₂) = 310.18 g/mol.
M(P) = 30.97 g/mol.
For one kilogram of phosphorus, we need:
M(Ca₃(PO₄)₂) : 2M(P) = m(Ca₃(PO₄)₂) : m(P).
310.18 g/mol : 61.94 g/mol = m(Ca₃(PO₄)₂) : 1000 g.
m(Ca₃(PO₄)₂) = 5007.75 g ÷ 1000 g/kg = 5.007 kg.
Mass of ore find from proportion:
m(Ca₃(PO₄)₂) : m(ore) = 56% : 100%.
m(ore) = 100% · 5.007 kg ÷ 58.6%.
m(ore) = 8.54kg.

5 0

3 years ago

112 g of aluminum carbide react with 174 g water to produce methane and aluminum hydroxide in the reaction shown below.

dolphi86 [110]

Answer: 4.999 moles of excess reactant will be left over.

Explanation:

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)