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MariettaO [177]
3 years ago
12

What volume of 0.100 M HCl will react completely with 50.00 mL of 0.200 M NaOH?

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
7 0
Equation of reaction
Hcl+NaoH-->Nacl+H2O
1:1
Using the formula CaVa/CbVb=na/nb
Ca(Concentation of acid)= 0.100M
Cb(Concentration of base)=0.200M
Va=?
VB=50.00ml
na=1
nb=1
from the formula
Va= CbVbna/Canb
Va= 0.2*50*1/0.1*1
=10/0.1=100ml
Therefore volume of acid = 100ml
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What is the total number of atoms in 0.20 mol of propanone, CH3COCH3?
Nutka1998 [239]

Answer:

1.2×10²³ atoms.

Explanation:

Data obtained from the question include:

Mole of propanone = 0.20 mole

Number of atoms of propanone =.?

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ atoms.

This implies that 1 mole of propanone also contains 6.022×10²³ atoms.

Thus, we can obtain the number of atoms in 0.20 mole of propanone as illustrated below:

1 mole of propanone contains 6.022×10²³ atoms.

Therefore, 0.20 mole of propanone will contain = 0.2 × 6.022×10²³ = 1.2×10²³ atoms.

Thus, 0.20 mole of propanone contain

1.2×10²³ atoms.

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2 years ago
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Explanation:

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Sliva [168]

Answer:

A

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heat energy is transfered through a hot object touching a cold object

5 0
3 years ago
A star is estimated to have a mass of 2.0 x 10 ^36kg. Assuming it to be a sphere of average radius of 7.0 x 10 ^5 km. Calculate
Montano1993 [528]

Answer:

<em>a)</em> <em>1.392 x 10^6 g/cm^3</em>

<em>b) 8.69 x 10^7 lb/ft^3</em>

<em></em>

Explanation:

mass of the star m =  2.0 x 10^36 kg

radius of the star (assumed to be spherical) r = 7.0 x 10^5 km = 7.0 x 10^8 m

The density of substance ρ = mass/volume

The volume of the star = volume of a sphere = \frac{4}{3}\pi  r^{3}

==> V = \frac{4}{3}*3.142*(7.0*10^8)^{3} = 1.437 x 10^27 m^3

density of the star ρ = (2.0 x 10^36)/(1.437 x 10^27) = 1.392 x 10^9 kg/m^3

in g/cm^3 = (1.392 x 10^9)/1000 = <em>1.392 x 10^6 g/cm^3</em>

in lb/ft^3 =  (1.392 x 10^9)/16.018 = <em>8.69 x 10^7 lb/ft^3</em>

6 0
2 years ago
Ions, isotope, average atomic mass fill in the blank
Zarrin [17]

For Row 1 according to the respective Column is

  • Zn^{2+} , 32 ,65 ,32 ,30 ,34 ,2+

For Row 2 according to the respective Column is

  • Mn, 25, 55, 25, 25,30, 3-

For Row 3 according to the respective Column is

  • P, 15, 31, 15 ,15 ,16 ,0

For Row 4 according to the respective Column is

  • O^{2-} , 8 ,16 ,8 ,6 ,8 , 2-

For Row 5 according to the respective Column is

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From the question we are told

Ions, isotope, average atomic mass fill in the blank

Generally

Where

  • Z signifies the Proton Number of the atom
  • A signifies Mass Number of the atom

Therefore

For Row 1 according to the respective Column is

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For Row 2 according to the respective Column is

  • Mn, 25, 55, 25, 25,30, 3-

For Row 3 according to the respective Column is

  • P, 15, 31, 15 ,15 ,16 ,0

For Row 4 according to the respective Column is

  • O^{2-} , 8 ,16 ,8 ,6 ,8 , 2-

For Row 5 according to the respective Column is

  • Na, 11, 23, 11, 10, 12, 1-

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