Answer:
Explanation:
For second order reaction
dC / dt = -k C²
dC /C² = - kdt
Integrating on both sides,
[- 1/C ] = - kt + P , P is a constant .
When t =0 , C = 1.33 M
P = - 1 / 1.33
[- 1/C ] =- - kt - 1 / 1.33
When t = 8.5
[- 1/C ] = - kt - 1 / 1.33
= - 1.18 x 8.5 - 1 / 1.33
= - 10.03 - .7519
= - 10.782
C = .0927 M
= .093 M
When energy is converted from one form into another, heat is lost at every sept along the way.
a. heat.
Answer:
The final and initial concentration of the acid and it's conjugate base are approximately equal, that is we use the weak acid approximation.
Explanation:
The Henderson-Hasselbalch is used to calculate the pH of a buffer solution. It depends on the weak acid approximation.
Since the weak acid ionizes only to a small extent, then we can say that [HA] ≈ [HA]i
Where [HA] = final concentration of the acid and [HA]i = initial concentration of the acid.
It also follows that [A^-] ≈ [A^-]i where [A^-] and[A^-]i refer to final and initial concentrations of the conjugate base hence the answer above.
