<span>(6.36x10^25)/(6.02*10^23) is approximately 105.6 moles</span>
Answer:
0.190L of hydrogen may be produced by the reaction.
Explanation:
Our reaction is:
3Mg + 2H₃PO₄ → Mg₃(PO₄)₂ + 3H₂
We need to determine the limting reactant. Let's find out the moles of each:
5.159×10²¹ atoms . 1 mol / 6.02×10²³ atoms = 0.00857 moles of Mg
55.23 g . 1 mol / 97.97 g = 0.563 moles of acid
2 moles of acid react to 3 moles of Mg
0.563 moles of acid may react to: (0.563 . 3) /2 = 0.8445 moles of Mg
Definetely the limting reactant is Mg.
As ratio is 3:3, 3 moles of Mg can produce 3 moles of hydrogen
Then, 0.00857 moles of Mg must produce 0.00857 moles of H₂
At STP, 1 mol of any gas occupies 22.4L
0.00857 mol . 22.4L / 1mol = 0.190L
I am pretty sure it is B. If it turns litmus paper red it is acidic. The other 2 make no sense.
I might be wrong tho.
Hope that helped☺️
Water has positive side and negative side. This is the reason why water can dissolve salt such sodium chloride. Example when sodium chloride dissociate in water it give Na+ ions and Cl- ions. the negative side of water attack the Na+ ions while the positive side of water attract Cl- ions