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3 years ago

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The largest segmented ground-based telescope is the Gran Telescopio Canarias in Spain. Its mirror is made up of 36 hexagonal seg

ments, which each have a side length of 0.9 meters. What is the area of one segment of Gran Telescopio Canarias’s mirror?

1 answer:

Marta_Voda [28]3 years ago

5 0

2.1 m²

so um it's a regular hexagon since all of its side lengths are equal.

Mark brainliest please

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Use the position function s(t) = –4.9t2 + 500, which gives the height (in meters) of an object that has fallen for t seconds fro

weqwewe [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is $v(3) = 29.4 \ m/s$

Step-by-step explanation:

From the question we are told that

$s(t) = -4.9t^2 + 500$

And

$\lim_{t \to a} \frac{s(a) - s(t)}{a-t}$

Generally s(t) at t = a is mathematically evaluated as

$s(a) = -4.9a^2+ 500$

So

$s(a) - s(t) = -4.9a^2 + 500 - ( -4.9t^2+500)$

$s(a) - s(t) = -4.9a^2 + 500 +4.9t^2-500)$

$s(a) - s(t) = 4.9(t^2 - a^2)$

Thus the velocity is represented as

$v(t) =\lim_{t \to a} \frac{s(a) - s(t)}{a-t} \equiv \lim_{t \to a} \frac{4.9(t^2 - a^2 )}{ a-t}$

=> $v(t) = \lim_{t \to a} - 4.9(a + t )$

=> $v(t) = -4.9 (a + a )$

=> $v(t) = -9.8a$

Now at t = 3

=> $v(3) = -9.8 (3)$

=> $v(3) = 29.4 \ m/s$

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4 years ago

Three tennis balls are stored in a cylindrical container with a height of 8 inches and a radius of 1.43 inches. The circumferenc

Rom4ik [11]

The complete question is
Three tennis balls are stored in a cylindrical container with a height of 8 inches and a radius of 1.43 inches. The circumference of a tennis ball is 8 inches. a) Find the volume of a tennis ball b) There are 3 tennis ball in the container Find the amount of space within the cylinder not taken up by the tennis balls. Round your answers to the nearest hundredth.

Part a)

we know that
length of a circumference=2*pi*r----------> r=length/(2*pi)---> 8/(2*pi)
r=1.27 in------> radius of tennis ball

volume of a tennis ball is equals to the volume of a sphere
[volume of a sphere]=(4/3)*pi*r³----> (4/3)*pi*1.27³---> 8.58 in³

the answer Part a) is
the volume of a tennis ball is 8.58 in³

Part b)
[volume of the container]=pi*r²*h-----> pi*1.43²*8----> 51.39 in³

[volume of 3 tennis balls]=8.58*3-----> 25.74 in³

the amount of space within the cylinder not taken up by the tennis balls is
51.39-25.74-----> 25.65 in³

the answer Part b) is
25.65 in³

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Rainbow [258]

Answer:

x=2

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answer:

C Is the corect answer

Step-by-step explanation:

Brcause you multiple the 4 and 8 = 38

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