Answer:its A ( the transport of nutrients,water,oxygen to body cells
Explanation:
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This is a double replacement reaction; the ions switch twice.
Answer:
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion. (option E)
Explanation:
Step 1: Data given
Volume = 500 mL = 0.500 L
The concentration sodium sulfate = 2.104 M
Step 2: The equation
Na2SO4 → 2Na+ + SO4^2-
For 1 mol Na2SO4 we have 2 moles sodium ion (Na+) and 1 mol sulfate ion (SO4^2-)
Step 3: Calculate the concentration of the ions
[Na+] = 2*2.104 M = 4.208 M
[SO4^2-] = 1*2.104 M = 2.104 M
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion. (option E)
Answer:
Pb(C2H3O2)2 + KI ----> PbI2 + KC2H3O2
Explanation:
all the numbers are written as subscripts
A substance that reduces the hydrogen ion concentration of a solution is <u>base</u>.
A base which thus completely dissociates in an aqueous solution is referred to as a strong base. These substances produce one or more hydroxide ions (OH-) per base molecule when they ionize in water. A weak base, on the other hand, only partially splits into its water-soluble ions.
The three definitions of "base" used in chemistry are Arrhenius base, Bronsted base, as well as Lewis base. The fact instead that bases react towards acids is acknowledged by all base definitions.
Therefore, a substance that reduces the hydrogen ion concentration of a solution is <u>base</u>.
To know more about hydrogen ion
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