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MA_775_DIABLO [31]
2 years ago
15

Please answer this question please brianlest

Chemistry
1 answer:
Arada [10]2 years ago
7 0

Answer:

yrr pls explain the question correctly , i didn't understand , rly sryyyyyyy

Explanation:

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What is the atomic number and name of an element that has 15 protons in its nucleus?
just olya [345]

Answer:

phosphorus.

Explanation:

The atomic number of phosphorus is 15 so the protons will be 15.

4 0
2 years ago
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Give the quantum values of n,l,m and s for nitrogen
sweet [91]
L = 0 to n-1. Hence, it can have values 0, 1, 2. 

<span>m = -l to +l. Hence, it can have values -2, -1, 0, 1, 2 </span>

<span>s = +1/2 and -1/2</span>

4 0
3 years ago
I NEED THE ANSWER QUICKKK!!!
julsineya [31]

Answer:  This is hard to do accurately, but here is my best assessment.

Explanation:

Experiment:  B  -  describes how the experiment was done

Conclusion:  A  -  The data support the prevailing hypothesis

Research:  D   -   This is what we analyzed

Analysis:  C  -  We compared the data

7 0
2 years ago
The molecule carbon disulfide (CS2) is nonpolar and has only London dispersion forces between the molecules. Carbon tetrachlorid
stepladder [879]

Answer:

Final Answer: boiling point and high

Explanation:

3 0
3 years ago
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An unknown liquid is composed of 34.31% c, 5.28% h, and 60.41% i. The molecular weight is 210.06 amu. What is the molecular form
ozzi

In an unknown liquid, the percentage composition with respect to carbon, hydrogen and iodine is 34.31%, 5.28% and 60.41% respectively.

Let the mass of liquid be 100 g thus, mass of carbon, hydrogen and oxygen will be 34.31 g, 5.28 g and 60.41 g respectively.

To calculate molecular formula of compound, convert mass into number of moles as follows:

n=\frac{m}{M}

Molar mass of carbon, hydrogen and iodine is 12 g/mol, 1 g/mol and 126.90 g/mol.

Taking the ratio:

C:H:I=n_{C}:n_{H}:n_{I}

Putting the values,

C:H:I=\frac{34.31 g}{12 g/mol}:\frac{5.28 g}{1 g/mol}:\frac{60.41 g}{126.90 g/mol}=6:11:1

Thus, molecular formula of compound will be C_{6}H_{11}I.

4 0
3 years ago
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