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earnstyle [38]
3 years ago
8

LA MATERIA SE PUEDE PRESENTAR COMO

Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:

La materia está constituida por átomos, que a su vez forman moléculas. Las moléculas constituyen la mínima parte en la que se puede fragmentar una sustancia para que conserve sus propiedades. Todo lo anterior permite que la materia se pueda presentar en estado sólido, líquido y gaseoso.

Explanation:

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B. Mechanical-  is NOT a type of adaptation

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3 years ago
Help please I will thank you
mart [117]
There should be 2 since there’s 2 D atoms in the reaction.
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Is mud a suspension, solution, or colloid?
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A shiny chunk of metal is found to have a mass of 37.28g. The metal is dropped into a graduated cylinder which contains 20.0 mL
Amanda [17]

Answer: The density of the material is 2.66 g/mL and it is likely this  is made of Aluminum

Explanation:

The first step to know the material of the chunk of metal is to calculate its density. The general formula for density is P (density) = \frac{m (mass)}{ v (volume)}. Moreover, in this case, it is known the mass is 37.28 g, but the volume is not directly provided. However, we know the water in the graduated cylinder had a volume of 20.0 mL and this increased to 34.0 mL when the chunk of metal is added, this means the volume of the metal is 14 mL (34.0 mL - 20.0 mL = 14 mL). Now let's calculate the density:

P = \frac{37.28g}{14.0mL}

P = 2.66 g/mL

This means the density of this metal is 2.66 g/mL, which can be rounded as 2. 7 g/mL, and according to the chart, this is the density of aluminum. Therefore, this material of this chunk is aluminum.

6 0
3 years ago
The molar solubility of C a ( O H ) 2 C a ( O H ) 2 was experimentally determined to be 0.019 M. Based on this value, what is th
Anuta_ua [19.1K]

Answer:

Ksp = 2.74 x 10⁻⁵

Explanation:

The solubility equilibrium for Ca(OH)₂ is the following:

  Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)

I                          0                0

C                       + s               + 2s

E                        s                   2s

According to the ICE table, the expression for the solubility product constant (Kps) is:

Ksp = [Ca²⁺] x ([OH⁻])² = s x (2s)² = 4s³

Then, we calculate Ksp from the solubility value (s):

s = 0.019 M

⇒ Ksp = 4s³ = 4 x (0.019)³ = 2.74 x 10⁻⁵

8 0
3 years ago
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