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Cloud [144]
3 years ago
6

Calculus, Limits and Continuity Can someone please answer/explain this question? Thank you.

Mathematics
1 answer:
lana [24]3 years ago
6 0

9514 1404 393

Answer:

  (A) -4 and -2

Step-by-step explanation:

The constant in the function tells you f(0) = 5.

You know that the positive leading coefficient means the value of f(x) will be negative for x-values smaller than some number. The offered answer choices indicate the value x = -4 is a lower bound on the value of c. So, -4 < c < 0, for sure.

To further refine the interval, you would need to know f(-2) and/or f(-1).

  f(-2) = (-2)³ -2(-2) +5 = -8 +4 +5 = 1

Then -4 < c < -2.

_____

I find a graphing calculator to be very helpful locating zeros of polynomials.

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C. Line 3

Step-by-step explanation:

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2 years ago
Without drawing the graphs, find the points of intersection of the lines:
tankabanditka [31]
The answer is (4,7) :)
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Who tryna help me lmaaoo
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It is b ok I got you
7 0
2 years ago
△FSB∼△ZDR .<br><br> What is the value of x?<br><br> Enter your answer.<br><br> How many units?
kari74 [83]
Answer: 22

---------------------------------------------------------

Explanation:

The triangles are similar, so we know the corresponding sides form ratios that are equal. 

Note how...
FS and ZD are the first two letters of FSB and ZDR respectively
FB and ZR are the first & last letters of FSB and ZDR respectively

Based on those two facts above, we can form this proportion
FS/ZD = FB/ZR
38/15.2 = 55/x

Solve for x
38/15.2 = 55/x
38*x = 15.2*55
38*x = 836
x = 836/38
x = 22

4 0
3 years ago
A company has developed a training procedure to improve scores on the SAT. Following the training, 100 high school students take
Pani-rosa [81]

Answer:

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  sample mean (x⁻ )  = 517

sample standard deviation (s) =90

Mean of the Population (μ) =500

<em>Null Hypothesis :- H₀ :  </em> (μ) =500

Alternative Hypothesis : H₁ :  μ ≠ 500

<u><em>Step(ii)</em></u>:-

Test statistic

                         t = \frac{x^{-} -mean}{\frac{s}{\sqrt{n} } }

                        t = \frac{517 -500}{\frac{90}{\sqrt{100} } }

                        t  =   1.717

<em>Level of significance</em>

                      ∝ = 0.05

                    t₀.₀₅ = 1.6604

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

<u><em>Conclusion</em></u>:-

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

3 0
3 years ago
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