3.5 M has 3.5 moles per litre
so we have one litre, so we need 3.5 moles
moles = mass/molarmass
3.5 * 23 = 80.5
Toxicants generally follow the Law of Diffusion , moving from areas of high concentration to areas of lower concentration.
<h3><u>What are Toxicants ?</u></h3>
Any hazardous chemical is a toxicant. Both naturally occurring and artificial toxicants have the potential to be harmful. A toxin, in contrast, is a poison created spontaneously by an organism (e.g. plant, animal, insect). The many toxicant categories may be present in the air, land, water, or food.
A substance is toxic if it has the potential to be harmful or have negative effects on health. Chemicals like polychlorinated biphenyls (PCBs) and dioxin, which are present at some hazardous waste sites, often cause people to worry.
<h3><u>What is the Law of Diffusion ?</u></h3>
Graham's law of diffusion states that the ratio of the diffusion rate of two gases is the same as the ratio of the square root of the molar mass of the gases.
To view more questions about Toxicants, refer to: brainly.com/question/5896648
#SPJ4
Answer:
B. Excited state
Explanation:
Energy levels higher than the ground state are called the excited states. This concept is based on the premise that electrons can move round the nucleus in certain permissibe orbits or energy levels.
The ground state is the lowest energy state available to the electron. This is usually the most stable state.
The excited state is any level higher than the ground state. An electron in an energy level has a definite amount of energy associated with it at that level.
Answer:
I) the heat capacity of ammonia(s)
II) the heat capacity of ammonia(ℓ)
IV) the enthalpy of fusion of ammonia
Explanation:
Initially, ammonia at 200 K is liquid. To calculate the change of enthalpy from 200 K to 195 K (melting point) we need to know the heat capacity of ammonia(ℓ).
At 195, ammonia is in the transition from liquid to solid (solidification). To calculate the change of enthalpy in that process we need to know the enthalpy of solidification of ammonia, which has the same value but opposite sign to the enthalpy of fusion of ammonia.
From 195 K to 0 K, ammonia is solid. To calculate the change of enthalpy in that process we need to know the heat capacity of ammonia(s).
