Answer:
2NH4NO3 —> 2N2 + O2 + 4H2O
Explanation:
We begin by writing the skeletal equation as shown below:
NH4NO3 —> N2 + O2 + H2O
The equation can be balance as follow:
There are 4 atoms of H on the left side of the equation and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:
NH4NO3 —> N2 + O2 + 2H2O
Now we have a total of 4 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 1/2 in front of O2 as shown below:
NH4NO3 —> N2 + 1/2O2 + 2H2O
Now, multiply through by 2 to clear the fraction as shown below
2NH4NO3 —> 2N2 + O2 + 4H2O
Now the equation is balanced
Answer:
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Explanation:
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There are two possible products from this elimination:
-2,3-dimethylbut-1-ene
-2,3-dimethylbut-2-ene
As the base is relatively unhindered, the reaction will form the Saytzeff product as the major product. The Saytzeff product is the most substituted alkene which is more stable due to hyperconjugation. In this reaction the Saytzeff product is 2,3-dimethylbut-2-ene.
It would be a triple bond because they overlap orbitals to share three pairs of electrons
The symbols indicate the physical state of each reactant