Answer:
Explanation:
Ratio of mass of C , N , H and O
= .8007 :0.9333:0.2016:2.133
Ratio of moles of C , N , H and O
= .8007/12 : .9333 / 14 : 0.2016 / 1 : 2.133/16
= .0667 : .0667: .2016 : .1333
= .0667 / .0667 : .0667 / .0667 : .2016 /.0667 : .1333 / .0667
= 1 : 1 : 3: 2
Hence empirical formula = CNH₃O₂
7 .
Weight of titanium Ti = 1.916 g
Weight of oxygen = 3.196 - 1.916 = 1.28 g
Ratio of weight of Ti and O
= 1.916 : 1.28
Ratio of moles of Ti and O
1.916/48 : 1.28/16 [ Molecular weight of Titanium is 48 ]
= .04 : .08
= .04/.04 : .08/.04
= 1 :2 .
Empirical formula
TiO₂
<span>When water decomposes into oxygen and hydrogen, the mass "Remains Constant" as according to Law of Conservation of mass, mass can neither be created not destroyed,.
In short, Your Answer would be Option A
Hope this helps!</span>
Answer: The image from the question has the correct answers.
Explanation:
As summarized in the attached table.
Answer:
The correct answer is cancer therapy, genetic engineering, and detecting thyroid malfunction.
Explanation:
There are numerous applications of radiation in medicine. The most well-known is the use of X-rays. Other than that radiations are also used in the treatment of cancer known as cancer therapy. It is also used in nuclear medicine therapy like the application of radioactive iodine in the treatment of thyroid issues like thyroid cancer. Radiation also has an application in genetic engineering that comprises the production of modifications in the hereditary units of prevailing animals and plants.
Answer:
a. Ksp = 4s³
b. 5.53 × 10⁴ mol³/dm⁹
Explanation:
a. Obtain an expression for the solubility product of AB2(S),in terms of s.
AB₂ dissociates to give
AB₂ ⇄ A²⁺ + 2B⁻
Since 1 mole of AB₂ gives 1 mole of A and 2 moles of B, we have the mole ratio as
AB₂ ⇄ A²⁺ + 2B⁻
1 : 1 : 2
Since the solubility of AB₂ is s, then the solubility of A is s and that of B is 2s
So, we have
AB₂ ⇄ A²⁺ + 2B⁻
[s] [s] [2s]
So, the solubility product Ksp = [A²⁺][B⁻]²
= (s)(2s)²
= s(4s²)
= 4s³
b. Calculate the Ksp of AB₂, given that solubility is 2.4 × 10³ mol/dm³
Given that the solubility of AB is 2.4 × 10³ mol/dm³ and the solubility product Ksp = [A²⁺][B⁻]² = 4s³ where s = solubility of AB = 2.4 × 10³ mol/dm³
Substituting the value of s into the equation, we have
Ksp = 4s³
= 4(2.4 × 10³ mol/dm³)³
= 4(13.824 × 10³ mol³/dm⁹)
= 55.296 × 10³ mol³/dm⁹
= 5.5296 × 10⁴ mol³/dm⁹
≅ 5.53 × 10⁴ mol³/dm⁹
Ksp = 5.53 × 10⁴ mol³/dm⁹
