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babunello [35]
2 years ago
15

What do you think explains why the larger elements are able to form in a supernova explosion? Use evidence from the Supernova 10

54 video and text to support your response. (Please answer in complete sentences. 3 points for a thorough explanation of why larger elements are able to form in a supernova explosion)
Chemistry
1 answer:
lubasha [3.4K]2 years ago
3 0

Larger elements are able to form in a supernova explosion because the star releases very large amounts of energy as well as neutrons, which allows elements heavier than iron to be produced.

<h3>What is Supernova?</h3>

This is referred to the explosion of a star and it resulting in larger elements being formed through a process known as nucleosynthesis and is usually accompanied by an increase in the brightness of the star.

The elements produced are usually larger than elements such as iron and examples include uranium, gold etc.

This is therefore the reason why it was chosen as the most appropriate choice.

Read more about Supernova here brainly.com/question/27492871

#SPJ1

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Determine the mass of 5.2 x 10 power of 21 molecules of propanol C3H7OH(l), on grams.
Alja [10]

n(\text{C}_3\text{H}_7\text{OH}) = N(\text{C}_3\text{H}_7\text{OH}) / N_A\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 5.2 \times 10^{21} / (6.02 \times 10^{23})\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 8.6 \times 10^{-3} \; \text{mol}

where N_A = 6.02 \times 10^{23}\; \text{mol}^{-1} the Avogadro's constant that relates the number of particles to their number, in the unit moles \text{mol}.

The molar mass of propanol- mass per mole propanol- can be directly deduced from its molecular formula with reference to a modern periodic table.

M(\text{C}_3\text{H}_7\text{OH}) = \underbrace{3 \times 12.01}_{\text{carbon}} + \underbrace{8 \times 1.008}_{\text{hydrogen}} + \underbrace{1\times 16.00}_{\text{oxygen}} = 60.09 \; \text{g} \cdot \text{mol}^{-1}

8.6 \times 10^{-3} \; \text{mol} of propanol molecules would thus have a mass of 8.6 \times 10^{-3} \; \text{mol} \times 60.09 \; \text{g} \cdot \text{mol}^{-1} = 0.52 \; \text{g}

5 0
4 years ago
A 40.0-mL sample of 0.100 M HNO2 (Ka = 4.6 x 10-4 .) is titrated with 0.200 M KOH. Calculate: a. the pH when no base is added b.
In-s [12.5K]

Answer:

a) 2.173

b) 20ml

c) 3.87

d) 4.35

e) 8.8

f) 12.45

Explanation:

chech the attachment for explanationns

4 0
3 years ago
What dose volume mean (in science)
IrinaVladis [17]
The definition in Volume is a the amount of space a substance or object occupies, or that is enclosed within a container, especially when great. For example "The sewer could not cope with the volume of rainwater" . You can say it in different ways, such as capacity, size, magnitude, mass, bulk, extent and more. I hope this helps :-).
3 0
4 years ago
Predict the following chemical formula for a compound between Al and S.
Alinara [238K]
Al2S3. Al has a +3 charge and S has a -2 charge, generally speaking
7 0
3 years ago
Read 2 more answers
What is the empirical formula of a compound that contains 49.4% K, 20.3% S, and 30.3% by mass? A) KSO3 B) K2SO3 C) KSO2 D) KSO E
yulyashka [42]

Answer: K_2SO_3.

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of K = 49.4 g

Mass of S = 20.3 g

Mass of O = 30.3 g

Step 1 : convert given masses into moles.

Moles of K=\frac{\text{ given mass of K}}{\text{ molar mass of K}}= \frac{49.4g}{40g/mole}=1.23moles

Moles of S= \frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{20.3g}{32g/mole}=0.63moles[/tex]

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{30.3g}{16g/mole}=1.89moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For K = \frac{1.23}{0.63}=2

For S =\frac{0.63}{0.63}=1

For O =\frac{1.89}{0.63}=3

The ratio of K: S:O = 2: 1: 3

Hence the empirical formula is K_2SO_3.

7 0
3 years ago
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