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dolphi86 [110]
3 years ago
13

Consider the oxidation of sodium metal to sodium oxide described by the balanced equation: 4 na + o2 ? 2 na2o. if 2.55 mol of so

dium reacts, what is the percent yield if the reaction actually gives 75.0 g of na2o?
Chemistry
1 answer:
Viefleur [7K]3 years ago
7 0
The balanced reaction:

<span>4Na + O2 = 2Na2O

We use the relation of the substances and the amount of sodium to determine the theoretical yield of the reaction. This yield is the amount produced if all the reactant is consumed.

2.55 mol Na (2 mol Na2O / 4 mol Na) ( 61.98 g / 1 mol ) = 79.02 g Na2O

Percent yield = 75.0 / 79.02 x 100 = 94.91%</span>
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What determines crystal size in minerals formed by lava or magma?
Burka [1]

Answer:

When magma cools, crystals form because the solution is super-saturated with respect to some minerals. If the magma cools quickly, the crystals do not have much time to form, so they are very small. If the magma cools slowly, then the crystals have enough time to grow and become large.

Explanation:

5 0
3 years ago
A silver coin with a mass of 14.1g has a density of 10.5 grams
Angelina_Jolie [31]

Answer:

1.34 cubic centimeter

Explanation:

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5 0
3 years ago
Which element would most likely be a shiny solid at room temperature and a good conductor of electricity?
Alborosie

Answer:

A

Explanation:

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7 0
3 years ago
if you react 100g of ammonium chloride with excess calcium oxide, what Is the theoretical yeild (in grams) of ammonia? when you
Maurinko [17]

Answer:

31.78 grams

25.55%

Explanation:

The balanced reaction for ammonium chloride with calcium oxide will be:

2NH4Cl + Ca(OH)2 ---> CaCl2 + 2NH3 + 2H2O

The molecular weight for ammonium chloride(NH4Cl ) is 53.49g/mol, while the molecular weight for ammonium(NH3) is 17g/mol. The number of theoretical yield of ammonia from 100g of ammonium chloride will be:

100g / (53.49g/mol) * 2/2  * 17g/mol= 31.78 grams

If the actual yield is 8.12g, the percent yield will be: 8.12g/31.78g * 100% =25.55%

4 0
3 years ago
How many moles of Fluorine (F2) are<br><br> needed to completely react 8.0<br><br> moles of NF3?
Anna [14]

Answer:

12 moles of F₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N₂ + 3F₂ —> 2NF₃

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Finally, we shall determine the number of mole of F₂ needed to produce 8 moles of NF₃. This can be obtained as illustrated below:

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Therefore, Xmol of F₂ will react to produce 8 moles of NF₃ i.e

Xmol of F₂ = (3 × 8)/2

Xmol of F₂ = 12 moles

Thus, 12 moles of F₂ is needed for the reaction.

8 0
3 years ago
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