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2 years ago

In this reaction what is the correct coefficient for sodium chloride? pb(no3)2 ? nacl → pbcl2 ? nano3

Chemistry

2 answers:

weqwewe [10]2 years ago

8 0

Answer:

Explanation:

The unbalanced reaction is shown below as:-

$Pb(NO_3)_2+NaCl\rightarrow PbCl_2+NaNO_3$

On the left hand side,

There is 1 lead atom and 2 nitrogen atoms and 6 oxygen atoms and 1 sodium atom and 1 chlorine atom

On the right hand side,

There is 1 lead atom and 2 chlorine atoms and 3 oxygen atoms and 1 sodium atom

Thus,

Right side, $NaNO_3$ must be multiplied by 2 so to balance nitrogen and oxygen.

Left side, $NaCl$ is multiplied by 2 so to balance the whole reaction.

Thus, the balanced reaction is:-

$Pb(NO_3)_2+2NaCl\rightarrow PbCl_2+2NaNO_3$

<u>Coefficient of the sodium chloride in the balanced equation - 2</u>

Dovator [93]2 years ago

4 0

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A saline solution similar to that used for intravenous drips is made by dissolving 0.45 g sodium chloride in 50.00 g water. Whic

beks73 [17]

Answer:

E) 1, 2, and 3

Explanation:

50g H2O + 0.45g NaCl --> 50.45g saline solution

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2 years ago

If 23.17 g of beryllium (Be) reacts with water at standard temperature and pressure,

emmainna [20.7K]

Volume of H2 produced = 57.6576 L

<h3>Further explanation</h3>

Given

23.17 g Be

Required

Volume of H2

Solution

Reaction

Be(s)+H2O(g)→BeO(s)+H2(g)

mol Be :

= 23.17 g : 9 g/mol

= 2.574

From the equation, mol H2 : mol Be = 1 : 1, so mol H2 = 2.574

Volume H2(assumed at STP, 1 mol=22.4 L) :

= 2.574 x 22.4 L

= 57.6576 L

5 0

2 years ago

EXPLAIN. List the steps that show the sun provides the energy for the surface ocean currents.

stiks02 [169]

The horizontal and vertical circulation of ocean waters are known as currents. The main causes of ocean currents include variation in water density, gravity, and wind friction. Surface ocean currents are primarily caused by wind.

4 0

3 years ago

What is the most likely evidence of an energy transformation taking place when a wite that is twisted and turned breaks

SashulF [63]

The most likely evidence of an energy transformation taking place when a <em>wire</em> is twisted and turned breaks is that the broken ends of the wire turn warm (even very hot if it was twisted and turned vigoroulsy).

The heat (thermal energy) evolves due to the internal friction developed by the relative motion of the internal particles of the wire, being kinetic energy transformed into heat energy.

It is the same phenomenon that is observed when a saw cuts a piece of metal and the reason why a cooling fluid is poured over the pieces of metal to avoid that the temperature raises too much.

6 0

2 years ago

Determine the standard enthalpy of formation of SrI2(s) using a Born–Haber cycle. Enthalpy of sublimation of Sr(s) = 164 kJ/mol

Nesterboy [21]

Answer:

Enthalpy of formation of strontium chloride, SrCl = -558.1 kJ/mol

Explanation:

Sr(s) -------> Sr(g) ΔHsublimation = +164 kJ/mol

Sr⁺(g) -------> Sr⁺(g) First Ionization energy, IE₁ = +549 kJ/mol

Sr⁺(g) -------> Sr²⁺(g) Second ionization energy, IE₂ = +1064 kJ/mol

I₂(s) --------> I₂(g) ΔHsublimation = +62.4 kJ/mol

I₂(g) -------> 2I(g) Bond dissociation energy, BE = +152.55 kJ/mol

2I(g) ----> 2I⁻(g) Electron affinity, EA = 2 (-295.15 kJ/mol) = -590.3 kJ/mol

Sr²⁺(g) + 2I⁻(g) ------> SrI₂(s) Lattice energy, LE = -1959.75 kJ/mol

Overall equation for the formation of SrCl₂ is given as:

Sr(s) + I₂(s) ----> SrI₂(s) ΔHformation = ?

Enthalpy of formation, ΔHformation = (ΔHsublimation of Sr(s) + IE₁ + IE₂ + ΔHsublimation of I₂(s) + BE + EA + LE)

ΔHformation = {164 + 549 + 1064 + 62.4 + 152.55 + (-590.3) + (-1959.75)} kJ/mol

Sr(s) + I₂(s) ----> SrI₂(s) ΔHformation = -558 kJ/mol

Therefore, enthalpy of formation of strontium chloride, SrCl = -558.1 kJ/mol

8 0

3 years ago