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fenix001 [56]
3 years ago
14

Mary and Jeff both have jobs at a baseball stadium selling bags of peanuts. They each get paid $12 per game

Mathematics
1 answer:
Anarel [89]3 years ago
6 0
A) 1.75p + 12 = 54
1.75p = 42
p = 24 bags

b) 1.75(70) + 12 = b
122.5 + 12 = b
b = $134.50
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Options are 264 414 2487 9948
Brums [2.3K]
Find total area

area=pir^2
d/2=r
12=d, 12/2=6=r

area=pi6^2=36pi, pi=3.14
area=113.04 square inches

22 per square inch

113.04 times 22=2486.88
rounded
2487 calories
7 0
3 years ago
If 27 x 34 = n, then which division equation is also true?
Nitella [24]

27 x 34 = 918

Correct division Equations are:

918 ÷ 34 = 27

and

918 ÷ 27 = 34

PS. PLZZZZZZZZZZZ give me brainliest!!!

5 0
3 years ago
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PLEASE HELP!! WILL MARK BRAINLIEST AND THANK YOU!!! IM DESPERATE!!!!
mel-nik [20]

Answer:

91 in²

Step-by-step explanation:

Area of tarpezoid = (sum of both bases x height) / 2

A = ((11 + 15) x 7) /2 = 91

5 0
3 years ago
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A store sells 12-packs of ballpoint pens for $1.09 each and composition books for $2.79 each. Cindy buys m packs of ballpoint pe
Ludmilka [50]
<span>There are two possible ways where you can express this. First, is by presenting the equation net of 5 percent which is "x=1.0355n+2.6505m". The other way to express such is by presenting it with gross amount which is "x= (1-0.05)(1.09n+2.79m)"
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5 0
3 years ago
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Simplify the expression csc(-x)/1+tan^2x)
Charra [1.4K]
Assuming ya meant \frac{csc(-x)}{1+tan^2(x)}

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos


for the pythaogreaon identity
cos^2(x)+sin^2(x)=1
divide both sides by cos^2(x)
1+tan^2(x)=sec^2(x) since \frac{sin(x)}{cos(x)}=tan(x)
subsitute
\frac{csc(x)}{sec^2(x)}

recall that csc(x)=\frac{1}{cos(x)}
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)
so we get

\frac{csc(x)}{sec^2(x)}
decompose them into \frac{1}{cos(x)} and \frac{1}{sin^2(x)} to get \frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}
multiply by \frac{sin^2(x)}{sin^2(x)} to get
\frac{sin^2(x)}{cos(x)}
we can furthur simlify to get
(\frac{sin(x)}{cos(x)})(sin(x))=tan(x)sin(x)
the expression simplifies to tan(x)sin(x)
5 0
3 years ago
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