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Murrr4er [49]
3 years ago
14

What is the area of a rectangle whose sides measure 2g and (g+5)

Mathematics
1 answer:
zvonat [6]3 years ago
4 0

Answer:

2g² + 10g

Step-by-step explanation:

Let the,

Length of the rectangle be " l ".

Base of the rectangle be " b ".

l = 2g

b = g + 5

Formula : -

Area of the rectangle = lb

Area of the rectangle

= 2g ( g + 5 )

= 2g ( g ) + 2g ( 5 )

= 2g² + 10g

Therefore,

the area of a rectangle whose sides measure 2g and ( g + 5 ) is 2g² + 10g.

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Answer:

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Step-by-step explanation:

a. Since the two base angles of this triangle are congruent, we can conclude that the triangle is <em>isosceles, </em>which means that the two base angles and sides are congruent.

Now, knowing that information, we can subtract 110 from 180 (the sum of all interior angles in a triangle) and we get 70. But this isn't our answer. This is the sum of both base angles. Since the base angles are congruent, we can divide the 70 by 2 to get the measure of ONE base angle, which is 35 degrees.

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2) The second approach is supplementary angles. Since we see that one of the base angles and <1 is on the same line, we can subtract 35 from 180 to find the measure of <1 to get 145 degrees.

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Step-by-step explanation:

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