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Murrr4er [49]
3 years ago
14

What is the area of a rectangle whose sides measure 2g and (g+5)

Mathematics
1 answer:
zvonat [6]3 years ago
4 0

Answer:

2g² + 10g

Step-by-step explanation:

Let the,

Length of the rectangle be " l ".

Base of the rectangle be " b ".

l = 2g

b = g + 5

Formula : -

Area of the rectangle = lb

Area of the rectangle

= 2g ( g + 5 )

= 2g ( g ) + 2g ( 5 )

= 2g² + 10g

Therefore,

the area of a rectangle whose sides measure 2g and ( g + 5 ) is 2g² + 10g.

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Use the Distributive Property to expand 9(3 + x).
tankabanditka [31]
Distribute the 9 to each term in the parentheses with multiplication.

9(3 + x) = 27 + x

But this is usually written as x + 27
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3 years ago
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The distance between capeton & Jonesville is 80 miles. The scale on the map is 0.75 in 10 Mi how far part are the cities on
ikadub [295]

Answer:

6 in = 80 miles

Step-by-step explanation:

Given that:

Distance between Capeton and Jonesville = 80 miles.

Map scale : 0.75 in = 10 miles ; this means 0.75 inches on the map represents 10 miles on land.

Hence, If ;

0.75 inches = 10 miles

x inches = 80 miles

Cross multiply :

10 * x = 80 * 0.75

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4 0
3 years ago
There are 2 questions pls answer fast
Furkat [3]

Answer:

Q1: B. UHWXUQV

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3 years ago
Find the 89th term of 25,35,45
MAXImum [283]

Answer:

The 89th term would be 895.

Step-by-step explanation:

There is a pattern of adding 10 each time. Notice that the 5 at the end doesn't change and that the first number continues (i.e. 2, 3, 4, 5, 6). All you have to do is add an 89 in front of the 5 and that is your answer, 895.

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3 years ago
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Giving 100 points.
Nitella [24]

Answer:

1.   <u>Cost per customer</u>:  10 + x

     <u>Average number of customers</u>:  16 - 2x

\textsf{2.} \quad  -2x^2-4x+160\geq 130

3.    $10, $11, $12 and $13

Step-by-step explanation:

<u>Given information</u>:

  • $10 = cost of buffet per customer
  • 16 customers choose the buffet per hour
  • Every $1 increase in the cost of the buffet = loss of 2 customers per hour
  • $130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

<u>Part 1</u>

<u></u>

<u>Cost per customer</u>:  10 + x

<u>Average number of customers</u>:  16 - 2x

<u>Part 2</u>

The cost per customer multiplied by the number of customers needs to be <u>at least</u> $130.  Therefore, we can use the expressions found in part 1 to write the <u>inequality</u>:

(10 + x)(16 - 2x)\geq  130

\implies 160-20x+16x-2x^2\geq 130

\implies -2x^2-4x+160\geq 130

<u>Part 3</u>

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

\implies -2x^2-4x+160\geq 130

\implies -2x^2-4x+30\geq 0

\implies -2(x^2+2x-15)\geq 0

\implies x^2+2x-15\leq  0

\implies (x-3)(x+5)\leq  0

Find the roots by equating to zero:

\implies (x-3)(x+5)=0

x-3=0 \implies x=3

x+5=0 \implies x=-5

Therefore, the roots are x = 3 and x = -5.

<u>Test the roots</u> by choosing a value between the roots and substituting it into the original inequality:

\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144

As 144 ≥ 130, the <u>solution</u> to the inequality is <u>between the roots</u>:  

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.  

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an <em>increase </em>in cost.  It does not confirm that if the cost is reduced (less than $10) the number of customers <em>increases </em>per hour.]

<u>Cost per customer</u>:  

x =0 \implies 10 + 0=\$10

x=3 \implies 10+3=\$13

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0
2 years ago
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