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Murrr4er [49]
2 years ago
14

What is the area of a rectangle whose sides measure 2g and (g+5)

Mathematics
1 answer:
zvonat [6]2 years ago
4 0

Answer:

2g² + 10g

Step-by-step explanation:

Let the,

Length of the rectangle be " l ".

Base of the rectangle be " b ".

l = 2g

b = g + 5

Formula : -

Area of the rectangle = lb

Area of the rectangle

= 2g ( g + 5 )

= 2g ( g ) + 2g ( 5 )

= 2g² + 10g

Therefore,

the area of a rectangle whose sides measure 2g and ( g + 5 ) is 2g² + 10g.

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Please Help!! Brainliest Answer! Thank you
stiks02 [169]

Answer:

A

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O = 26.6

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Q = 63.4

To determine side lengths: a^2 + b^2 = c^2

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*Variable c is always hypotenuse*

Need more information so find either b or c through SOH, CAH, TOA

SOH: sine = opposite/hypotenuse

CAH: cos = adjacent/hypotenuse

TOA: tan = opposite/adjacent

tan26.6/1 = b/4

Cross multiply

1 × b = 4 × tan26.6

b = 4tan26.6

b = 2.003050791

b is about 2

b = PQ

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Plug b value into pythagorean theorm

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5 0
3 years ago
Read 2 more answers
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Arisa [49]

Answer:

Option A

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By using the definition of an exterior angle of a triangle,

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Substitute the measures of the angles from the picture attached,

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x = 7

Therefore, Option A will be the correct option.

7 0
3 years ago
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