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3 years ago

What is the area of a rectangle whose sides measure 2g and (g+5)

Mathematics

1 answer:

zvonat [6]3 years ago

4 0

Answer:

2g² + 10g

Step-by-step explanation:

Let the,

Length of the rectangle be " l ".

Base of the rectangle be " b ".

l = 2g

b = g + 5

Formula : -

Area of the rectangle = lb

Area of the rectangle

= 2g ( g + 5 )

= 2g ( g ) + 2g ( 5 )

= 2g² + 10g

Therefore,

the area of a rectangle whose sides measure 2g and ( g + 5 ) is 2g² + 10g.

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Finger [1]

Answer:

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Step-by-step explanation:

First we need to calculate the change in the area of Terry's room this is

108 ft2 - 96 ft2 = 12 ft2

Then we use a direct proportion in order to find the percentage

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Solvin for p we have that

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Answer:

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3 years ago

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A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

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Answer:

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