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Olin [163]
2 years ago
6

What is an equation for the line perpendicular to y=-1/8x+6 that passes through (-3,-10)

Mathematics
1 answer:
Ainat [17]2 years ago
4 0

Answer:

y = 8x + 14

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - \frac{1}{8} x + 6 ← is in slope- intercept form

with slope m = - \frac{1}{8}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{1}{8} } = 8 , then

y = 8x + c ← is the partial equation

To find c substitute (- 3, - 10 ) into the partial equation

- 10 = - 24 + c ⇒ c = - 10 + 24 = 14

y = 8x + 14 ← equation of perpendicular line

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Maru [420]

Answer:

The standard form of y = 3 x + 1 is         -3x + y = 1 .

The standard form of y  = 4x - 7 is         -4x + y = -7.

Step-by-step explanation:

Here the given equation are:

y = 3 x + 1

and y  = 4x - 7

The above equations are of the form:  y = m x + C

Now, the STANDARD FORM of the equation is Ax + By  = C

<u>Consider equation 1: </u>

y = 3 x + 1

or, y - 3x  = 1

or. -3x + y = 1

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y = 4 x - 7

or, y - 4x  = -7

or. -4x + y = -7

⇒ The equation -4x + y = -7 is in STANDARD FORM.

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Answer:

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{:}\leadsto\sf {\dfrac {3}{7}}

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<h2>____________________</h2>

{:}\leadsto\sf {\dfrac {9}{21}}\iff {\dfrac {7}{21}}

{:}\leadsto\sf {\dfrac{9}{21}} \gt {\dfrac {7}{21}}

\therefore\sf {\dfrac {3}{7}} \gt {\dfrac {7}{21}}

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