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2 years ago

What is an equation for the line perpendicular to y=-1/8x+6 that passes through (-3,-10)

Mathematics

1 answer:

Ainat [17]2 years ago

4 0

Answer:

y = 8x + 14

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - $\frac{1}{8}$ x + 6 ← is in slope- intercept form

with slope m = - $\frac{1}{8}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{1}{8} }$ = 8 , then

y = 8x + c ← is the partial equation

To find c substitute (- 3, - 10 ) into the partial equation

- 10 = - 24 + c ⇒ c = - 10 + 24 = 14

y = 8x + 14 ← equation of perpendicular line

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The rectangle below has a area x^2-x-72 square meters and a length of x+8 meters what expression represents the width of the rec

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ANSWER

$w = (x - 8)$

EXPLANATION

The given rectangle has area,

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To find the width, we need to factor, the expression for the area.

We split the middle term to get,

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