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dmitriy555 [2]
3 years ago
5

Can some one please help me thank u.

Computers and Technology
1 answer:
masya89 [10]3 years ago
5 0

Answer:

 A) self- evaluation

Explanation:

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Select the correct line of missing code to create an output of "hello."
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Answer:

B

Explanation:

This feels like an error on the question issuer's part.

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You realize your computer has been infected with malware. It seems as if someone is controlling your computer from a remote loca
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Worm malware

Explanation:

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3 years ago
CAN SOMEONE PLEASE PLEASE HELP ME OUT !!!!
34kurt

Answer:the answer is A

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3 years ago
Which search strategy is most similar to greedy search?
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Answer:

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Explanation:

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8 0
3 years ago
Question is attached as image, please help :>
harkovskaia [24]

Answer:

Proved

Explanation:

Given

X = (a.\bar b)+(\bar a.b)

(a + b)\ .  \frac{}{a.b}

Required

Find out why they represent the same

To do this, we simplify either (a + b)\ .  \frac{}{a.b} or X = (a.\bar b)+(\bar a.b)

In this question, I will simplify (a + b)\ .  \frac{}{a.b}

Apply de morgan's law

(a + b)\ .  \frac{}{a.b} = (a + b) . (\bar a + \bar b)

Apply distribution property

(a + b)\ .  \frac{}{a.b} = a.\bar a + a.\bar b + \bar a . b + b . \bar b

To simplify, we apply the following rules:

a.\bar a = 0 --- Inverse law

b.\bar b = 0 --- Inverse law

So, the expression becomes

(a + b)\ .  \frac{}{a.b} = 0 + a.\bar b + \bar a.b + 0

(a + b)\ .  \frac{}{a.b}  = a.\bar b + \bar a.b

Rewrite as:

(a + b)\ .  \frac{}{a.b}  = (a.\bar b)+(\bar a.b)

From the given parameters:

X = (a.\bar b)+(\bar a.b)

This implies that:

(a + b)\ .  \frac{}{a.b} when simplified is X or (a.\bar b)+(\bar a.b)

3 0
3 years ago
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