The specific heat of the gold is 1.67 (=125/(3*(43-18)) joule/ gram oC based on its heat energy, change in temperature and mass. This problem can be solved using the heat energy formula which stated as Q=c*m*(deltaT). In this formula, Q is the heat energy, c is the specific heat, m is the object's mass, and deltaT is the change in the temperature of the reaction<span>.</span>
Answer:
- 55
Step-by-step explanation:
I read (-99/3^2)*5
(-99/9)*5
(-11)*5 = - 55
Answer:
33+15w=3w-w+4w
33+15w - 15w=3w-w+4w -15w
33 = 2w + 4w -15w
33 = 6w -15w
33 = -9w
33/9 = -9/9w
3.66 = w
Step-by-step explanation:
33+15w=3w-w+4w
33+15w - 15w=3w-w+4w -15w
33 = 2w + 4w -15w
33 = 6w -15w
33 = -9w
33/9 = -9/9w
3.66 = w
Answer:
25
Step-by-step explanation:
