λ = c : f
λ = 3 x 10⁸ : 1.05 x 10⁸
λ = 2.86 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.86
E = 1.896 x 10⁻³³ J
λ = 3 x 10⁸ : 1.011 x 10⁸
λ = 2.97 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.97
E = 1.97 x 10⁻³³ J
λ = 3 x 10⁸ : 1.05 x 10⁸
λ = 2.96 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.96
E = 1.96 x 10⁻³³ J
The answer is C. The ball and floor had friction between them causing the ball to stop rolling
Answer:
Explanation:
I dont know if this will help but A two force member is a body that has forces (and only forces, no moments) acting on it in only two locations. In order to have a two force member in static equilibrium, the net force at each location must be equal, opposite, and collinear.
The car accelerates with magnitude <em>a</em> such that
31.3 m/s = 25.6 m/s + <em>a</em> (5.4 s)
→ <em>a</em> = (31.3 m/s - 25.6 m/s) / (5.4 s) ≈ 1.056 m/s²
Then the applied force has a magnitude <em>F</em> of
<em>F</em> = (1430 kg) <em>a</em> ≈ 1500 N