Answer:
a) P = 2319.6[kPa]; b) 2.6%
Explanation:
Since the problem data is not complete, the following information is entered:
A 1.78-m3 rigid tank contains steam at 220°C. One-third of the volume is in the liquid phase and the rest is in the vapor form. Determine (a) the pressure of the steam, and (b) the quality of the saturated mixture.
From the information provided in the problem we can say that you have a mixture of liquid and steam.
a) Using the steam tables we can see (attached image) that the saturation pressure at 220 °C is equal to:
![P_{sat} =2319.6[kPa]](https://tex.z-dn.net/?f=P_%7Bsat%7D%20%3D2319.6%5BkPa%5D)
![v_{f}=0.001190[m^{3}/hr]\\v_{g}=0.08609[m^{3}/hr]\\](https://tex.z-dn.net/?f=v_%7Bf%7D%3D0.001190%5Bm%5E%7B3%7D%2Fhr%5D%5C%5Cv_%7Bg%7D%3D0.08609%5Bm%5E%7B3%7D%2Fhr%5D%5C%5C)
b) Since the specific volume of the gas and liquid is known, we can find the mass of each phase using the following equation:
![m_{f}=\frac{V_{f} }{v_{f} } \\m_{g}=\frac{V_{g} }{v_{g} } \\where:\\V_{f}=volume of the fluid[m^3]\\v_{f}=specific volume of the fluid [m^3/kg]\\](https://tex.z-dn.net/?f=m_%7Bf%7D%3D%5Cfrac%7BV_%7Bf%7D%20%7D%7Bv_%7Bf%7D%20%7D%20%20%5C%5Cm_%7Bg%7D%3D%5Cfrac%7BV_%7Bg%7D%20%7D%7Bv_%7Bg%7D%20%7D%20%20%5C%5Cwhere%3A%5C%5CV_%7Bf%7D%3Dvolume%20of%20the%20fluid%5Bm%5E3%5D%5C%5Cv_%7Bf%7D%3Dspecific%20volume%20of%20the%20fluid%20%5Bm%5E3%2Fkg%5D%5C%5C)
We know that the volume of the fluid is equal to:
![V_{f}=1/3*V_{total} \\V_{total}=1.78[m^3]\\](https://tex.z-dn.net/?f=V_%7Bf%7D%3D1%2F3%2AV_%7Btotal%7D%20%20%5C%5CV_%7Btotal%7D%3D1.78%5Bm%5E3%5D%5C%5C)
Now we can find the mass of the gas and the liquid.
![m_{f}=\frac{1/3*1.78}{0.001190} \\m_{f}=498.6[kg]\\m_{g}=\frac{2/3*1.78}{0.08609}\\m_{g}=\ 13.78[kg]](https://tex.z-dn.net/?f=m_%7Bf%7D%3D%5Cfrac%7B1%2F3%2A1.78%7D%7B0.001190%7D%20%20%5C%5Cm_%7Bf%7D%3D498.6%5Bkg%5D%5C%5Cm_%7Bg%7D%3D%5Cfrac%7B2%2F3%2A1.78%7D%7B0.08609%7D%5C%5Cm_%7Bg%7D%3D%5C%2013.78%5Bkg%5D)
The total mass is the sum of both
![m_{total} =m_{g} + m_{fluid} \\m_{total} = 498.6 + 13.78\\m_{total} = 512.38[kg]](https://tex.z-dn.net/?f=m_%7Btotal%7D%20%3Dm_%7Bg%7D%20%2B%20m_%7Bfluid%7D%20%5C%5Cm_%7Btotal%7D%20%3D%20498.6%20%2B%2013.78%5C%5Cm_%7Btotal%7D%20%3D%20512.38%5Bkg%5D)
The quality will be equal to:
The Correct answer would be D. Work equals force times distance.
Comets are like "dirty snowballs"; frozen gasses with dust and rocks in them. Each pass near the Sun causes the comet's nucleus to be exposed to intense sunlight, which causes some tiny fraction of the gas to evaporate and carry some of the dust and rock away into space. The gas and dust, near the Sun, cause the comet's "tail", and repeated passes cause dust and rock to spread out along most of the orbit of a comet. When the Earth enters one of these trails of old comet dust, we have meteor showers.
<span>On rare occasions, comets break apart or even more rarely, crash into planets. In 1994, the comet Shoemaker-Levy 9 broke apart and then collided with the planet Jupiter.</span>
Answer:
True
Explanation:
When a satellite is orbiting the earth, the centripetal force is balanced by the gravitational force as :
...........(1)
Where
M is the mass of the earth
m is the mass of the planet
From equation (1), the speed of the satellite depends only on the mass of the earth and the orbital radius.
So, If a payload of material is added until it doubles the satellite's mass, the earth's pull of gravity on this satellite will double but the satellite's orbit will not be affected. It is true.
Answer: vacuum
Explanation: The vacuum is the medium from where the sound wave cannot pass. A vacuum is basically an area without any air. Since the sound wave is a mechanical wave that's why it cannot travel through a medium where there is no matter of vibrations to works in, i.e, it can't travel through a vacuum.
