Part 1- An ideal gas, initially at a volume of 1.71429 L and pressure of 7 kPa, undergoes isothermal expansion until its volume
is 6 L and its pressure is 2 kPa. Calculate the work done by the gas during this process. Answer in units of J.
Part 2- Find the heat added to the gas during this process.
Answer in units of J.
Part 2- Find the heat added to the gas during this process.
Answer in units of J.
1 answer:
Part 1- The work done by the gas during this process will be 5.65 ×10⁻³ kJ.
Part 2-The heat added to the gas during this process will be 5.65 ×10×10⁻³ kJ.
<h3>What is work done by the gas?</h3>Work is the product of pressure p and volumes V during a volume change for such a gas. The work seems to be the area under the curve that indicates how the state changes.
The work done under the isothermal process is;
For the isothermal process;
ΔU=0
Hence, the work done, and the heat added by the gas during this process will be 5.65 ×10⁻³ kJ and 5.65 ×10×10⁻³ kJ respectively.
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Answer:
b. Jupiter’s greater gravity has compressed the layers, so they are closer together there.
Explanation:
The value for Jupiter mass is 1.8981×10²⁷kg, while the mass of Saturn is 5.6832×10²⁶kg, so the different layers of clouds in Jupiter will be submitted to a greater gravitational pull because it has a bigger mass, as is established in the law of universal gravitation:
(1)
Where m1 and m2 are the masses of two objects, G is the gravitational constant and r is the distance between the two objects.
As it can be seen in equation 1, the gravitational force is directly proportional to the product of the masses of the objects, so if the mass increase the gravitational force will do it too.
For the case of Saturn, it has a lower mass so its layers of clouds will suffer a weaker gravitational pull. That leads to the three clouds being more spacing that the ones of Jupiter.