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enyata [817]
3 years ago
6

How much work is done on 10.0 c of charge to move it through a potential diffrence of 9.0 v in 10.0s

Physics
1 answer:
GenaCL600 [577]3 years ago
4 0
We need more evidence to be provided
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as your roller coaster climbs to the top of the steepest hill on its track when does the first car have the greatest potential e
pochemuha
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What is the kinetic energy of a 0.25kg ball rolling at a speed of 2.5m/s
Lisa [10]

Answer:

Explanation:

Kinetic Energy formula:

KE = \frac{1}{2}mv²

m=mass

v=speed

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m=0.25kg

v=2.5m/s

Plug the values in:

KE = 1/2(0.25kg)(2.5m/s)²

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Lucas is carrying his rock collection into class. He carries 30 pounds of rare rocks 15 feet into Classroom 6. It takes him 3 mi
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A solid uniform cylinder of mass 4.1 kg and radius 0.057 m rolls without slipping at a speed of 0.79 m/s. What is the cylinder’s
Amiraneli [1.4K]

Answer:

The cylinder’s total kinetic energy is 1.918 J.

Explanation:

Given that,

Mass = 4.1 kg

Radius = 0.057 m

Speed = 0.79 m/s

We need to calculate the linear kinetic energy

Using formula of linear kinetic energy

K.E_{l}=\dfrac{1}{2}mv^2

K.E_{l}=\dfrac{1}{2}\times4.1\times(0.79)^2

K.E_{l}=1.279\ J

We need to calculate the rotational kinetic energy

K.E_{r}=\dfrac{1}{2}\times I\omega^2

K.E_{r}=\dfrac{1}{2}\times\dfrac{1}{2}\times mr^2\times(\dfrac{v}{r})^2

K.E_{r}=\dfrac{1}{4}\times m\times v^2

K.E_{r}=\dfrac{1}{4}\times4.1\times(0.79)^2

K.E_{r}=0.639\ J

The total kinetic energy is given by

K.E=K.E_{l}+K.E_{r}

K.E=1.279+0.639

K.E=1.918\ J

Hence, The cylinder’s total kinetic energy is 1.918 J.

8 0
3 years ago
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