CAN SOME ONE ANSWER THIS ILL GIVE ALL MY POINTS AND BRAINLIEST PLEASE

Mathematics

1 answer:

kotegsom [21]2 years ago

5 0

1: KIH because of alternate exterier (or ACF because of verticle angle)

2. x

3. CFG

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Production times are evenly distributed between 8 and 15.8 minutes and production times are never outside of this interval. What

dezoksy [38]

Answer:

29.49% probability that a production time is between 9.7 and 12 minutes

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d, in which d is greater than c, is given by the following formula.

$P(c \leq X \leq d) = \frac{d - c}{b-a}$

Production times are evenly distributed between 8 and 15.8 minutes and production times are never outside of this interval.

This means that $a = 8, b = 15.8$

What is the probability that a production time is between 9.7 and 12 minutes?

$d = 12, c = 9.7$ .

$P(c \leq X \leq d) = \frac{d - c}{b-a}$

$P(9.7 \leq X \leq 12) = \frac{12 - 9.7}{15.8 - 8} = 0.2949$

29.49% probability that a production time is between 9.7 and 12 minutes

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2 years ago

A line, y = mx + b, passes through the point (1, 6) and is parallel to

koban [17]

Answer: b=6

Step-by-step explanation:

6 is in the y intercept place so it equals 6

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2 years ago

Graph the first six terms of a sequence where a1 = −10 and d = 3.

Neko [114]

notice the first term is -10, and the common difference is 3, so we add 3 to get the next term.

$\bf \begin{array}{cccll}\stackrel{x}{n}&term&\stackrel{y}{value}\\\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\1&a_1&-10\\\\2&a_2&\stackrel{-10+3}{-7}\\\\3&a_3&\stackrel{-7+3}{-4}\\\\4&a_4&\stackrel{-4+3}{-1}\\\\5&a_5&\stackrel{-1+3}{2}\\\\6&a_6&\stackrel{2+3}{5}\end{array}$