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marshall27 [118]
3 years ago
5

If y = kx, what is the value of k if y = 20 and x = 0.4? A)5 B)8 C)9.6 D)50

Mathematics
2 answers:
lara31 [8.8K]3 years ago
7 0

Given expression :

  • y = kx

let's plug the value of x as 0.4 and y as 20 in the given equation :

  • 20 = 0.4k

  • k = 20 ÷ 0.4

  • k = 50

correct choice - D. 50

JulsSmile [24]3 years ago
5 0

\\ \sf\longmapsto y=kx

\\ \sf\longmapsto k=\dfrac{y}{x}

  • put values

\\ \sf\longmapsto k=\dfrac{20}{0.4}

\\ \sf\longmapsto k=50

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A shipment of 50 precision parts including 4 that are defective is sent to an assembly plant. The quality control division selec
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Answer:

0.3968 = 39.68% probability this shipment passes inspection.

Step-by-step explanation:

The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

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C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

50 parts means that N = 50

4 defective means that k = 4

10 are chosen, which means that n = 10

What is the probability this shipment passes inspection?

Probability that none is defective, so:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968

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11y/11 = 3x/11

y = 3x/11

<u>NOW LET'S DIVIDE BOTH SIDES BY </u><u>x</u><u> TO GET </u><u>x</u><u> AS THE DENOMINATOR OF </u><u>y</u><u>.</u>

y = 3x/11

y/x = (3x/11)/x

y/x = (3x/11) * 1/x

y/x = 3/11

Therefore, y:x = 3:11

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