Answer:
Explanation:
r(t) = A(cos wt i + sin wt f)
= A cos wt i + A sin wt j
x = A cos wt
y = A sin wt
radius r
r² = x² + y² ( This is equation of a circle with radius r )
= A² cos² wt +A² sin² wt
= A²
r = A
radius r = A
b )
speed = dr/dt
v = - Aw sinwt i + Aw coswt j
magnitude of velocity
I v I= Aw √(sin²wt + cos²wt)
= Aw ( constant )
acceleration
= dv / dt = - Aw² cos wt - Aw² sinwt
magnitude of acceleration
I a I = Aw²
= r w²
d ) centripetal force = m acceleration
m w² A
=
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Answer:
5.448 g/cm³
Explanation:
Density: This is defined as the ratio of the mass of a body to its volume.
The unit of density is kg/m³ other sub units are g/cm³, mg/mm³.
From the question,
D = m/πr²h......................... Equation 1
Where D = density, m = mass, r = radius, h = height.
Given: m = 9.58 g, r = 8/2 mm = 4 mm = 0.4 cm, h = 3.5 cm
Substitute this values into equation 1
D = 9.58/(3.14×0.4²×3.5)
D = 5.448 g/cm³
Hence the density of the metal rod is 5.448 g/cm³
Answer:
c) 0.16 m/s2
Explanation:
The computation of the acceleration during the first km of travel is shown below
Given that
Final velocity = v = 42 m/s
Initial velocity = u = 0 m/s
Distance = 5.6km
Based on the above information, we need to apply the following formula
As we know that
= 0.1575 m/s ^2
hence, the correct option is c. 0.16 m.s^2
