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2 years ago

3 What is the displacement of a satellite when it makes a complete round along its circular path?

Physics

1 answer:

kirill [66]2 years ago

4 0

Answer:

Explanation:

The displacement is zero since it goes in a full circle and ends up where it started.

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When two trains, going in opposite directions, are passing on tracks that are laid out close together, the train cars can often

Afina-wow [57]

<h3>Answer:</h3>

"<u>Therefore, the speed of the air decreases, the pressure acting on the two trains increases (by Bernoulli's principle), and the two trains lean in toward one another</u>."

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3 years ago

Read 2 more answers

A test car is driving toward a solid crash-test barrier with a speed of 46 mi/h. Two seconds prior to impact, the car begins to

Mekhanik [1.2K]

Answer:

we have to measure distances and time, possibly with an automated system since the values are very small

Explanation:

For this exercise we can use the relationship between momentum and momentum

I = ∫ F dt = Δp

F t = m $v_{f}$ - mv₀

In the exercise they indicate that the final speed is zero

F t = - m v₀

F = -m v₀ / t

With this equation we can find what measurements should be carried out.

To find the speed with which the car collides with the wall, less measure the displacement and its time during the braking process before reaching the wall and from here find the speed with which it reaches the wall.

During the impact, we must find the time that the vehicle is in contact with the wall in the first approach is equal to the time that the car takes to reach the final speed of zero.

In summary we have to measure distances and time, possibly with an automated system since the values are very small

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4 years ago

A 3.0 kg mass is released from rest at point A. The mass slides along the curved surface to point B in 6.0 seconds. Point B is 2

timurjin [86]

Answer:

option d) -9 J

Explanation:

Given:

Mass, m = 3.0 kg

time, t = 6.0 seconds

Velocity of mass, v = 2.0 m/s

height, h = 2 m

Now, using the concept of work-Energy theorem

we have

Net work done = change in kinetic energy

Work done by gravity + work done by the friction = Final kinetic energy - Initial kinetic energy

mgh + $W_f$ = $\frac{1}{2}mv^2-0$

on substituting the values in the above equation, we get

3 × 9.8 × 2 + $W_f$ = $\frac{1}{2}\times 3\times2^2$

58.8 + $W_f$ = 6

$W_f$ = -52.8 J

here negative sign depicts that the work is done against the motion of the mass

also,

Power = (Work done)/time

Power = -52.8/6 = -8.8 W ≈ 9 J

Hence, option d) -9 J is correct

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3 years ago

Describe the relationship of attractive forces between molecules

Ede4ka [16]

<span>Describe the relationship of attractive forces between molecules and the ability of a solvent to dissolve a substance. Solvents can dissolve a substance only if the attraction of the solvent molecules is greater than the attraction between the molecules of the substance.</span>

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3 years ago

Two objects of same material are travelling near you. Object A is a 1.9 kg mass traveling 8 m/s; object B is a 2 kg mass traveli

Alex73 [517]

To determine the object which could give the greatest impact we will apply the concept of momentum. The object that has the highest momentum will be the object that will impact the strongest. Our values are

Mass of Object A

$m_A=1.9 kg$