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oksano4ka [1.4K]
3 years ago
11

To solve: x + 8 = 40

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
4 0

Well, to solve, you would subtract 8 from both sides, which means x would end up equaling 32.

X=32

mars1129 [50]3 years ago
3 0
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Free_Kalibri [48]

Answer:

T(2, -7) = (4, -10)

Step-by-step explanation:

T(x, y) = (x + 2, y - 3)

T(2, -7) = (2 + 2, -7 - 3)

T(2, -7) = (4, -10)

3 0
3 years ago
A room has a rectangular floor that is 15 feet by 21 feet. What is the area of the floor in square yards ? ​
Soloha48 [4]

Answer:

Hey There!

Let's solve...

Here it is a rectangular floor with length =21 cm and width =15cm

So

area = l \times w \\  = 21 \times 15 \\  = 315 {ft}^{2} \\  \\

So now We need to convert it to yards square

315ft^{2} \times  \frac{ {1yd}^{2} }{ {9ft}^{2} } \\  \\  =  \cancel{315ft^{2}}  \: ^{35}  \times  \frac{ {1yd}^{2} }{ \cancel{9 {ft}^{2} }}  \\  \\  = 35 {yd}^{2}

So how this 9 ft^2 came??

Let's know

ft \to \: yards \\  \\ 3ft = 1yd \\  \\  {3ft}^{2} =  {1yd}^{2}  \\  \\  \boxed{ {9ft}^{2} =  {1yd}^{2}}

<h2>I hope it is helpful to you...</h2><h3>Cheers!_______</h3>
8 0
3 years ago
Read 2 more answers
In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it
gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0
4 years ago
Don’t understand #11 A,B, and C help please
Fiesta28 [93]
I set it in a big problem. Since you know that all the angles of a triable add up to 180,
m<a + m<b + m<c = 180, plug in equations/values
(36) + (3x+12) + (3x+18) = 180, subtract 36
3x+12 + 3x+18 = 144, combine like terms,
6x+30 = 144, subtract 30,
6x=114, divide by 6,
x=19. Plug in X to the equations for m<b and m<c
4 0
3 years ago
F(x) = x^2. What is g(x).
exis [7]

The answer is C because you just have to plug in the given point to the different answers.

7 0
4 years ago
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